我正在使用bootable model trait为模型注册某些事件,使用我的特性。然而,我遇到了一个问题,试图模拟使用该特性的模型。具体来说,当模型的一个模拟版本被实例化时,它的引导代码同意它应该有一个bootMyTrait方法,但是当它试图调用它时却找不到它。
Sample Repository用于下面的操作,其中包含要重放的命令。
举个例子,这里有一个特点:
namespace App;
trait MyTrait
{
public static function bootMyTrait()
{
print("Booting MyTrait\n");
}
}以及一个使用它的模型:
namespace App;
use Illuminate\Database\Eloquent\Model;
class MyModel extends Model
{
use MyTrait;
}实例化模型正常工作。这显示了所需的输出:
$model = new MyModel();然而,试图模仿这一模式是不合作的。这是:
use Illuminate\Foundation\Testing\WithoutMiddleware;
use Illuminate\Foundation\Testing\DatabaseMigrations;
use Illuminate\Foundation\Testing\DatabaseTransactions;
class ExampleTest extends TestCase
{
/**
* A basic functional test example.
*
* @return void
*/
public function testTraitBooting()
{
$model = $this->getMock('App\MyModel');
}
}
Fails. Adding some debugging to Eloquent:
/**
* Boot all of the bootable traits on the model.
*
* @return void
*/
protected static function bootTraits()
{
$class = static::class;
foreach (class_uses_recursive($class) as $trait) {
print("\nTesting that class: $class has method: " . $method = 'boot'.class_basename($trait) . " because of Trait: $trait\n");
if (method_exists($class, $method = 'boot'.class_basename($trait))) {
print("Class: $class has method: $method \n");
try {
forward_static_call([$class, $method]);
} catch (\PHPUnit_Framework_MockObject_BadMethodCallException $e) {
print("Class: $class failed calling $method\n");
throw $e;
}
}
}
}给了我们这样的失败:
PHPUnit 5.1.0 by Sebastian Bergmann and contributors.
E 1 / 1 (100%)
Testing that class: Mock_MyModel_9ee820db has method: bootMyTrait because of Trait: App\MyTrait
Class: Mock_MyModel_9ee820db has method: bootMyTrait
Class: Mock_MyModel_9ee820db failed calling bootMyTrait
Time: 129 ms, Memory: 18.00Mb
There was 1 error:
1) ExampleTest::testTraitBooting
PHPUnit_Framework_MockObject_BadMethodCallException:
mock-bootable-laravel-model-trait/vendor/laravel/framework/src/Illuminate/Database/Eloquent/Model.php:326
mock-bootable-laravel-model-trait/vendor/laravel/framework/src/Illuminate/Database/Eloquent/Model.php:309
mock-bootable-laravel-model-trait/vendor/laravel/framework/src/Illuminate/Database/Eloquent/Model.php:296
mock-bootable-laravel-model-trait/vendor/laravel/framework/src/Illuminate/Database/Eloquent/Model.php:277
mock-bootable-laravel-model-trait/tests/ExampleTest.php:16我也尝试过用几种不同的方式创建模拟。以DatabaseSoftDeletingTraitTest为例:
use Illuminate\Foundation\Testing\WithoutMiddleware;
use Illuminate\Foundation\Testing\DatabaseMigrations;
use Illuminate\Foundation\Testing\DatabaseTransactions;
use Mockery as m;
class ExampleTest extends TestCase
{
/**
* A basic functional test example.
*
* @return void
*/
public function testTraitBooting()
{
$mock = m::mock('App\MyModel');
$mock->shouldReceive('bootMyTrait')->once();
}
}但在这里,bootMyTrait从未被称为:
PHPUnit 5.1.0 by Sebastian Bergmann and contributors.
E 1 / 1 (100%)
Time: 149 ms, Memory: 19.25Mb
There was 1 error:
1) ExampleTest::testTraitBooting
Mockery\Exception\InvalidCountException: Method bootMyTrait() from Mockery_0_App_MyModel should be called
exactly 1 times but called 0 times.
mock-bootable-laravel-model-trait/vendor/mockery/mockery/library/Mockery/CountValidator/Exact.php:37
mock-bootable-laravel-model-trait/vendor/mockery/mockery/library/Mockery/Expectation.php:271
mock-bootable-laravel-model-trait/vendor/mockery/mockery/library/Mockery/ExpectationDirector.php:120
mock-bootable-laravel-model-trait/vendor/mockery/mockery/library/Mockery/Container.php:297
mock-bootable-laravel-model-trait/vendor/mockery/mockery/library/Mockery/Container.php:282
mock-bootable-laravel-model-trait/vendor/mockery/mockery/library/Mockery.php:142
mock-bootable-laravel-model-trait/vendor/laravel/framework/src/Illuminate/Foundation/Testing/TestCase.php:122因此,我可以将我在引导方法中所做的代码移动到一个ServiceProvider中,但是接下来我需要注册使用该特性的每个模型。这感觉很脏,使用引导方法似乎是合适的。所以我想我不是撞上了窃听器,就是在不正确地嘲弄使用特征的模型。我看过getMockForTrait,但我也需要被模仿的实例来扩展雄辩(一些特征的方法称为雄辩的方法)
如果有人看到我错过了什么(或者我完全走错了路),非常感谢
发布于 2016-04-21 13:30:57
经过一些测试后,我相信这样的方法足以测试它:
$mock = m::mock('App\MyModel')->makePartial();
$mock->shouldReceive('bootMyTrait')->once();
$mock->__construct();解释:
$mock = m::mock('App\MyModel')->makePartial();
我们创建模拟,但我们使其部分,因为我们想要使用默认的类构造函数和其他方法。这意味着我们不覆盖的所有方法都将从原始的App\MyModel类中使用$mock->shouldReceive('bootMyTrait')->once();
这应该是显而易见的--我们希望验证bootMyTrait方法是否运行了1次$mock->__construct();
这样,我们就可以运行默认的类构造函数。在创建模拟时,似乎没有使用构造函数,所以我们不能用另一种方式测试它。如果要确保启动原始类构造函数,则需要手动启动对象构造函数方法。https://stackoverflow.com/questions/36580310
复制相似问题