我试图检查我用Raspberry pi的相机捕捉到的png的每个像素,并有选择地更改高于或低于某个r、g或b值的像素。我知道这是一个效率很低的算法,我只是想了解一下python脚本。我的代码是基于@Constantin的代码的,问题是:如何读取Python中给定像素的RGB值?,他的代码在下面。
import png, array
point = (2, 10) # coordinates of pixel to be painted red
reader = png.Reader(filename='image.png')
w, h, pixels, metadata = reader.read_flat()
pixel_byte_width = 4 if metadata['alpha'] else 3
#The line below is, I think wrong. I'll point out the what I did in my code below
pixel_position = point[0] + point[1] * w
new_pixel_value = (255, 0, 0, 0) if metadata['alpha'] else (255, 0, 0)
pixels[
pixel_position * pixel_byte_width :
(pixel_position + 1) * pixel_byte_width] = array.array('B', new_pixel_value)
output = open('image-with-red-dot.png', 'wb')
writer = png.Writer(w, h, **metadata)
writer.write_array(output, pixels)
output.close()我把它改成了这个
#!/usr/bin/python
import png, array
reader = png.Reader(filename='test.png')
w, h, pixels, metadata = reader.read_flat()
pixel_byte_width = 4 if metadata['alpha'] else 3
for x in range(w):
for y in range(h):
point_index = x+(y-1)*w#This is the bit that I said I'd fix above.
r = pixels[point_index * pixel_byte_width + 0]
g = pixels[point_index * pixel_byte_width + 1]
b = pixels[point_index * pixel_byte_width + 2]
pixel = pixels[point_index * pixel_byte_width :
(point_index+1) * pixel_byte_width]
#Above we have all the info about each byte, and below is our devious plan
new_pixel = (0, 0, 0, 0) if metadata['alpha'] else (0, 0, 0)
#if g > 175:
pixel = array.array('B', new_pixel)
output = open('test_edited.png', 'wb')
writer = png.Writer(w, h, **metadata)
writer.write_array(output, pixels)
output.close()所发生的是圆周率思考了一两分钟,然后我可以打开一个新的png,完全相同。我的脚本遗漏了什么,或者在Raspbian上有一个比python更好的逐点处理平台?
非常感谢!
发布于 2016-04-08 23:36:03
如果您对新库开放,我建议使用pillow,它是Python (PIL)的继任者。它要简单得多,而且不限于巴布亚新几内亚。文件在这里。
from PIL import Image, ImageDraw
img = Image.open('image.png')
img = img.convert("RGB") # Make sure we are in 8-bit RGB
draw = ImageDraw.Draw(img)
for y in range(img.height):
for x in range(img.width):
# getpixel returns a tuple with (R, G, B)
if img.getpixel((x, y))[1] > 175: # If too green
draw.point((x,y), '#000000') # Color syntax is CSS-like
img.save('test_edited.png', 'PNG')
# You can also use img.show() in a graphical environmenthttps://stackoverflow.com/questions/36509305
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