在WebSphere中注入时出错

Question

我继承了一个遗留应用程序，最初是用WebSphere 6.1构建的，然后迁移到WebSphere 8.0，运行JPA2.0和openJPA，没有问题。出于战略原因，我们正在向WebSphere自由迁移。我们首先在WebSphere经典8.5.5.8和JPA上进行了测试，而实体管理器在那里没有问题。然而，关于自由8.5.5.8，我得到以下例外：

java:comp/env/com.xxx.xxxx.service.CHServiceBean/em :javax.ejb.EJBException应用程序的CHServiceEJB.jar模块中的CHServiceBean组件的javax.persistence.EntityManager类型的javax.persistence.EntityManager引用无法解析。在com.ibm.wsspi.injectionengine.InjectionBinding.getInjectionObject(InjectionBinding.java:1493) .由: err javax.ejb.EJBException引起的err :不能解析javax.ejb.EJBException应用程序的CHServiceEJB.jar模块中CHServiceBean组件的javax.persistence.EntityManager类型的CHServiceBean引用。在内部类中的com.ibm.wsspi.injectionengine.InjectionBinding.getInjectionObject(InjectionBinding.java:1493)错误

我遇到了另一个EJB注入问题，这个问题通过绑定文件的配置得到了解决，但是我无法解决这个问题。我有两个应用程序，每个应用程序都有自己的EAR文件，但都运行在相同的自由JVM中。应用程序A运行前端/UI逻辑，而应用程序B是后端EJB / JPA接口。在项目方面，JPA应用程序被设置为2.0 (我想要2.1，但是基于另一个线程，JPA2.0和EJB3.1是尽可能高的，我在这里的另一个线程主题是->Eclipse Juno and JPA 2.1 support)。

这是我的server.xml文件：

    <server description="new server">

    <!-- Enable features -->
    <featureManager>
        <feature>javaee-7.0</feature>
        <feature>localConnector-1.0</feature>
        <feature>distributedMap-1.0</feature>
        <feature>adminCenter-1.0</feature> 
        <feature>ssl-1.0</feature>
        <feature>usr:webCacheMonitor-1.0</feature>
        <feature>webCache-1.0</feature>
        <feature>ldapRegistry-3.0</feature>
    </featureManager>

    <!--  Admin Center Config Start -->
    <!-- To access this server from a remote client add a host attribute to the following element, e.g. host="*" -->
    <httpEndpoint host="*" httpPort="9080" httpsPort="9443" id="defaultHttpEndpoint"/>

    <keyStore id="defaultKeyStore" password="xxxxxx"/> 

    <basicRegistry id="basic"> 
          <user name="admin" password="xxxxx"/> 
          <user name="nonadmin" password="xxxxxx"/> 
    </basicRegistry> 

    <administrator-role> 
      <user>admin</user>
    </administrator-role>

    <remoteFileAccess> 
       <writeDir>${server.config.dir}</writeDir> 
    </remoteFileAccess>

    <!-- Automatically expand WAR files and EAR files -->
    <applicationManager autoExpand="true"/>
    <applicationMonitor updateTrigger="mbean"/>

    <enterpriseApplication id="CHNewCHRDMEAR" location="CHNewCHRDMEAR.ear" name="CHNewCHRDMEAR">
        <application-bnd>
            <security-role name="AllAuthenticated">
                <special-subject type="ALL_AUTHENTICATED_USERS"/>
            </security-role>
        </application-bnd>
    </enterpriseApplication>
    <enterpriseApplication id="CHServiceEAR" location="CHServiceEAR.ear" name="CHServiceEAR"/>

    <!--  JAAS Authentication Alias (Global) Config -->
    <authData id="dbUser" password="{xor}MzhmJT06ajI=" user="dbUser"/>

    <!--  JDBC Driver and Datasource Config -->
    <library id="DB2JCC4Lib">
        <fileset dir="C:\DB2\Jars" includes="db2jcc4.jar db2jcc_license_cisuz.jar"/>
    </library>

    <dataSource containerAuthDataRef="dbUser" id="CHTEST2" jndiName="jdbc/nextgen" type="javax.sql.XADataSource">
        <jdbcDriver libraryRef="DB2JCC4Lib"/>
        <properties.db2.jcc databaseName="CHTEST2" password="{xor}MzhmJT06ajI=" portNumber="60112" serverName="server.com" sslConnection="false" user="dbUser"/>
        <containerAuthData password="{xor}MzhmJT06ajI=" user="dbUser"/>
    </dataSource>

    <dataSource id="CHTEST2_RO" jndiName="jdbc/nextgen_RO" type="javax.sql.XADataSource">
        <jdbcDriver libraryRef="DB2JCC4Lib"/>
        <properties.db2.jcc databaseName="CHTEST2" password="{xor}MzhmJT06ajI=" portNumber="60112" serverName="server.com" sslConnection="false" user="dbUser"/>
        <containerAuthData password="{xor}MzhmJT06ajI=" user="dbUser"/>
    </dataSource>
<!-- More in file, but no included...-->
</server>

这是我的persistence.xml文件：

<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
          http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
        version="2.0">
    <persistence-unit name="CHService" transaction-type="JTA">
    <jta-data-source>jdbc/nextgen</jta-data-source>
    <exclude-unlisted-classes>true</exclude-unlisted-classes>
    <properties>
        <property name="openjpa.jdbc.TransactionIsolation" value="read-uncommitted" /></properties></persistence-unit>
    <persistence-unit name="CHServiceRO" transaction-type="JTA">
        <jta-data-source>jdbc/nextgen_RO</jta-data-source>
        <exclude-unlisted-classes>true</exclude-unlisted-classes>
        <properties>
            <property name="openjpa.jdbc.TransactionIsolation" value="read-uncommitted" />
</properties>
</persistence-unit>
</persistence>

我*相信我们完全依靠注入来获取jndi查找的上下文，但这是因为在我们的代码中看不到对任何JPA特定JNDI名称的初始上下文的调用。下面是我来自EJB项目的两个模拟会话bean：

a. CHService豆：

    @Stateless
@TransactionManagement(TransactionManagementType.CONTAINER)
@Local({ CHServiceLocal.class })
@Remote({ CHServiceRemote.class })
@Interceptors({ CHServiceLog.class })
@Resources({
        @Resource(name = "jdbc/nextgen", mappedName = "jdbc/nextgen", authenticationType = AuthenticationType.APPLICATION, shareable = true, type = javax.sql.DataSource.class),
        @Resource(name = "services/cache/CHBluepages", mappedName = "services/cache/CHBluepages", authenticationType = AuthenticationType.APPLICATION, shareable = true, type = com.ibm.websphere.cache.DistributedMap.class),
        @Resource(name = "services/cache/CHGeneric", mappedName = "services/cache/CHGeneric", authenticationType = AuthenticationType.APPLICATION, shareable = true, type = com.ibm.websphere.cache.DistributedMap.class) })
public class CHServiceBean extends AbstractCHServiceImpl implements
        CHService {

    @PersistenceContext(unitName = "CHService")
    private EntityManager em;

b. CHServiceRO豆：

@Stateless
@TransactionManagement(TransactionManagementType.CONTAINER)
@Local({CHServiceLocalRO.class})
@Remote({CHServiceRemoteRO.class})
@Interceptors({CHServiceROLog.class})
@Resources({
    @Resource(name="jdbc/nextgen_RO", mappedName="jdbc/nextgen_RO", authenticationType=AuthenticationType.APPLICATION, shareable=true, type=javax.sql.DataSource.class),
    @Resource(name="jdbc/nextgen", mappedName="jdbc/nextgen", authenticationType=AuthenticationType.APPLICATION, shareable=true, type=javax.sql.DataSource.class),
    @Resource(name="services/cache/CHBluepages", mappedName="services/cache/CHBluepages", authenticationType=AuthenticationType.APPLICATION, shareable=true, type=com.ibm.websphere.cache.DistributedMap.class),
    @Resource(name="services/cache/CHGeneric", mappedName="services/cache/CHGeneric", authenticationType=AuthenticationType.APPLICATION, shareable=true, type=com.ibm.websphere.cache.DistributedMap.class)
})
public class CHServiceBeanRO implements CHServiceRO {

    @PersistenceContext (unitName="CHServiceRO") private EntityManager em;

    private CHServiceBase ch;

    @PostConstruct
    private void init() { ch = new CHServiceBase(em); }

下面是前端应用程序的Web.xml调用JPA应用程序的片段：

<resource-ref id="ResourceRef_1436377001246">
        <res-ref-name>jdbc/nextgen</res-ref-name>
        <res-type>javax.sql.DataSource</res-type>
        <res-auth>Application</res-auth>
        <res-sharing-scope>Shareable</res-sharing-scope>
    </resource-ref>
    <resource-ref id="ResourceRef_1436377001247">
        <res-ref-name>jdbc/nextgen_RO</res-ref-name>
        <res-type>javax.sql.DataSource</res-type>
        <res-auth>Application</res-auth>
        <res-sharing-scope>Shareable</res-sharing-scope>
    </resource-ref>

基于Gas关于这一主题的文章：java.lang.ClassCastException,Getting Entitymanager Via JNDI Lookup

我还尝试用以下条目更新web.xml：

<persistence-unit-ref>
  <persistence-unit-ref-name>chJPA</persistence-unit-ref-name>
  <persistence-unit-name>CHService</persistence-unit-name>
</persistence-unit-ref>
<persistence-unit-ref>
  <persistence-unit-ref-name>chJPA_RO</persistence-unit-ref-name>
  <persistence-unit-name>CHServiceRO</persistence-unit-name>
</persistence-unit-ref>

和Bean代码，其中包括：

@PersistenceContext(name = "chJPA", unitName = "CHService")

和

@PersistenceContext (name="chJPA_RO", unitName="CHServiceRO")

获得相同的错误，只需使用不同的jndi名称，即java:comp/env/chJPA引用类型为javax.persistence.EntityManager的CHServiceBean com.......etc等。

最后，根据这篇文章：Error while accessing EntityManager - openjpa - WAS liberty profile，也许我不能拥有完整的JavaEE 7特性并运行JPA2.0？请指点！

Answer 1

正如您在文章中所提到的-您不能将<feature>javaee-7.0</feature>与JPA2.0一起使用，因为它支持2.1，这就是为什么您有冲突。

所以你有两个选择：

• 要么使用Java EE7和JPA2.1
• 或者只是启用所需的Java 6特性，然后使用JPA2.0

由于您正在从WAS8.0迁移，而WAS8.0目前还不支持EE7，所以使用第二个选项可能更容易。因此，尝试删除javee-7.0特性，并添加ejbLite-3.1和jpa-2.0以及任何需要更多内容的内容。