我使用的API使用的是XML而不是JSON。对于如何将以下XML转换为JSON或如何正确使用ngFor指令中的数据,有什么建议吗?
另外,在这里可以观察到吗?
<case-file>
<serial-number>123456789</serial-number>
<transaction-date>20150101</transaction-date>
<case-file-header>
<filing-date>20140101</filing-date>
</case-file-header>
// ...
<classifications>
<classification>
<international-code-total-no>1</international-code-total-no>
<primary-code>025</primary-code>
</classification>
</classifications>
</case-file>
<case-file>
<serial-number>234567890</serial-number>
<transaction-date>20160401</transaction-date>
<case-file-header>
<filing-date>20160401</filing-date>
</case-file-header>
//...
<classifications>
<classification>
<international-code-total-no>1</international-code-total-no>
<primary-code>042</primary-code>
</classification>
</classifications>
</case-file>export class apiService {
constructor (private http: Http) {}
private _apiUrl = 'app/api';
getCaseFile () {
return this.http.get(this._apiUrl)
//conversion to JSON here?
.map(res => <CaseFile[]> res.json().data)
.catch(this.handleError);
}
private handleError (error: Response) {
console.error(error);
return Observable.throw(error.json().error || 'Server error');
}
}
<div *ngFor="#cf of case-file">{{case-file.serial-number}}</div>发布于 2016-04-02 06:37:36
基于库http://goessner.net/download/prj/jsonxml/,我实现了一个示例来接收Angular2数据并将它们解析为一个Angular2应用程序:
var headers = new Headers();
(...)
headers.append('Accept', 'application/xml');
return this.http.get('https://angular2.apispark.net/v1/companies/', {
headers: headers
}).map(res => JSON.parse(xml2json(res.text(),' ')));为了能够使用库,您需要首先解析XML字符串:
var parseXml;
if (typeof window.DOMParser != "undefined") {
parseXml = function(xmlStr) {
return ( new window.DOMParser() ).parseFromString(xmlStr, "text/xml");
};
} else if (typeof window.ActiveXObject != "undefined" &&
new window.ActiveXObject("Microsoft.XMLDOM")) {
parseXml = function(xmlStr) {
var xmlDoc = new window.ActiveXObject("Microsoft.XMLDOM");
xmlDoc.async = "false";
xmlDoc.loadXML(xmlStr);
return xmlDoc;
};
} else {
throw new Error("No XML parser found");
}见这个问题:
参见这个plunkr:https://plnkr.co/edit/dj63ASQAgrNcLLlwyAum?p=preview。
发布于 2016-12-18 09:38:42
我宁愿使用npm模块,而不是Javascript,因为
我做了这样的事。
var parser = new xml2js.Parser({explicitArray : false});
//used xml2js parser from npm (https://www.npmjs.com/package/xml2js)
//and in my service i used this
this.http.get(this.newsURL)
.flatMap(res=>{
return Observable.fromPromise(this.getJSON(res.text()))
})
.catch((error:any) => Observable.throw(error.json().error || 'Server error'));发布于 2017-05-03 06:52:15
如果您正在使用POST和获取XML响应:使用xml2js - https://www.npmjs.com/package/xml2js
https://stackoverflow.com/questions/36368405
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