我现在使用的是最基本的代码,它仍然不起作用:
from flask import Flask, render_template
from flaskext.mysql import MySQL
mysql = MySQL()
app = Flask(__name__)
# MySQL configurations
app.config['MYSQL_DATABASE_USER'] = 'root'
app.config['MYSQL_DATABASE_PASSWORD'] = ''
app.config['MYSQL_DATABASE_DB'] = 'people'
app.config['MYSQL_DATABASE_HOST'] = 'localhost'
mysql.init_app(app)
@app.route('/test')
def test():
conn = mysql.connect()
cursor = conn.cursor()
sql = "SELECT * from tbl_user"
cursor.execute(sql)
results = cursor.fetchall()
cursor.close()
conn.close()
return results
if __name__ == "__main__":
app.run(debug=True)我尝试通过Mysql cli在本地主机上连接到我的db,它工作得很好。我使用了mysql -u根目录,它接受它,然后我使用用户,它工作得很好,然后我就可以做select语句了。
下面是我遇到的错误:
Traceback (most recent call last):
File "C:\Python27\lib\site-packages\flask\app.py", line 1836, in __call__
return self.wsgi_app(environ, start_response)
File "C:\Python27\lib\site-packages\flask\app.py", line 1820, in wsgi_app
response = self.make_response(self.handle_exception(e))
File "C:\Python27\lib\site-packages\flask\app.py", line 1403, in handle_exception
reraise(exc_type, exc_value, tb)
File "C:\Python27\lib\site-packages\flask\app.py", line 1817, in wsgi_app
response = self.full_dispatch_request()
File "C:\Python27\lib\site-packages\flask\app.py", line 1478, in full_dispatch_request
response = self.make_response(rv)
File "C:\Python27\lib\site-packages\flask\app.py", line 1577, in make_response
rv = self.response_class.force_type(rv, request.environ)
File "C:\Python27\lib\site-packages\werkzeug\wrappers.py", line 847, in force_type
response = BaseResponse(*_run_wsgi_app(response, environ))
File "C:\Python27\lib\site-packages\werkzeug\wrappers.py", line 57, in _run_wsgi_app
return _run_wsgi_app(*args)
File "C:\Python27\lib\site-packages\werkzeug\test.py", line 871, in run_wsgi_app
app_rv = app(environ, start_response)
TypeError: 'tuple' object is not callable但是正如你所看到的,一旦我使用了烧瓶,我就会得到这个错误。
发布于 2016-04-01 17:12:17
这个问题与flaskext.mysql和db连接无关。在@app.route('/test')语句中,返回一个元组,这是从数据库中选择的结果。在水瓶中,您应该返回一些适切。
发布于 2016-04-01 19:58:46
视图应该返回一个模板或HTML代码(以字符串格式)。我猜您试图显示数据库查询的结果,所以正确的方法是使用render_template()函数通过模板传递数据。看看这里:http://flask.pocoo.org/docs/0.10/quickstart/#rendering-templates
https://stackoverflow.com/questions/36361467
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