我试图使用float3缓冲区border作为数据结构。它在使用Intel OpenCL SDK4.4,Intel iCore7执行内核时崩溃。不幸的是,我还没有发现3D索引(i, y, x)到线性索引adr=WIDTH2*i+WIDTH*y+x中的任何索引错误。我错过了什么?
以下是缓冲区定义(使用OpenCL C++包装器v1.2):
m_numPixels(width*width),
m_inBuffer(getContext(), CL_MEM_READ_ONLY | CL_MEM_ALLOC_HOST_PTR,
sizeof(float)*(width*width), NULL),
m_inBuffer2(getContext(), CL_MEM_READ_ONLY | CL_MEM_ALLOC_HOST_PTR,
sizeof(float)*(width*width), NULL),
m_backBuffer(getContext(), CL_MEM_READ_ONLY,
sizeof(float)*(width*width), NULL),
m_borderBuffer(getContext(), CL_MEM_READ_WRITE,
(3*sizeof(float))*(10*width*width), NULL),
m_outBuffer(getContext(), CL_MEM_READ_WRITE | CL_MEM_ALLOC_HOST_PTR,
4*(width*width), NULL),下面是内核代码:
__kernel void computeMedial (__global const float* height, // input height
__global const float* height2, // input height, previous frame
__global const float* background, // input background
__global float3* border, // border datastructure
__global uchar4* output, // output image
float thres,
uint width,
uint ls,
float scale)
{
uint x = get_global_id(0);
uint y = get_global_id(1);
const uint WIDTH2 = width*width;
const uint WIDTH = width;
// access pixel (x, y)
float2 c00 = (float2)(x, y);
float h00 = array_height(height, height2, width, c00);
if (x < 4 || x > width-5 || y < 4 || y > width-5) { // border location
return;
}
if (h00 < thres-10 || h00 > thres+10) { // not in thres interval
return;
}
output[y*WIDTH+x] = colorUCHAR(0, y, x); // writing output image
// test
for (uint i=0; i<ls; ++i) { // ls<=7 ok, ls==8/9/10 crashes
uint adr = WIDTH2*i+WIDTH*y+x;
border[adr] = (float3)(0);
}
}发布于 2016-03-25 20:47:24
border中存在对齐问题。在cl_platform.h状态中:
/* cl_float3 is identical in size, alignment and behavior to cl_float4. See section 6.1.5. */
typedef cl_float4 cl_float3;使用cl_*类型来避免此类问题是个好主意,因此您可以通过以下方式创建border缓冲区:
m_borderBuffer(getContext(), CL_MEM_READ_WRITE, (sizeof(cl_float3))*10*width*width), NULL),https://stackoverflow.com/questions/36224071
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