Java 21卡

Question

我有一项任务，我有困难。重点是让程序打印出带有blackjack值的卡片。它不需要实际将卡片加在一起，而只需要显示卡片的名称和值。

我的麻烦就在显示后面的号码，王牌，国王，皇后和杰克。我的代码是

import static java.lang.System.*;
public class Card
{
public static final String FACES[] = {"ZERO","ACE","TWO","THREE","FOUR",
        "FIVE","SIX","SEVEN","EIGHT","NINE","TEN","JACK","QUEEN","KING"};

//instance variables
private String suit;
private int face;

//constructors
public Card( String s, int f)
{
    suit = s;
    face = f;
}

// modifiers
public void setFace( int f)
{
    face = f;
}

public void setSuit( String s)
{
    suit = s;
}

//accessors
public String getSuit()
{
    return suit;
}

public int getFace()
{
    return face;
}

//toString
public String toString()
{
    return FACES[face] + " of " + suit;
}
 }

import static java.lang.System.*;
import java.awt.Color;

public class CardRunner
{
public static void main( String args[] )
{
    Card one = new Card("SPADES", 9);
    out.println(one.getSuit());
    out.println(one.getFace());

    Card two = new Card("DIAMONDS", 1);
    out.println(two);
    two.setFace(3);
    out.println(two);

    Card three = new Card("CLUBS", 4);
    out.println(three);

    Card four = new Card("SPADES", 1);
    out.println(four);

    Card five = new Card("HEARTS", 13);
    out.println(five);

    Card six = new Card("HEARTS", 11);
    out.println(six);

    Card seven = new Card("CLUBS", 12);
    out.println(seven);     
}
}

我在想，我会添加一个方法，调用超级(s，f)，因为这是我们正在学习的，作业的重点是使用对超级的调用。我只是很难让它显示数字。

我的产出是：

SPADES
9
ACE of DIAMONDS
THREE of DIAMONDS
FOUR of CLUBS
ACE of SPADES
KING of HEARTS
JACK of HEARTS
QUEEN of CLUBS

我需要的输出是：

SPADES 
9 
ACE of DIAMONDS 
THREE of DIAMONDS 
FOUR of CLUBS 
ACE of SPADES 11 
KING of HEARTS 10 
JACK of HEARTS 10
QUEEN of CLUBS 10

Answer 1

只需为卡片的实际值存储另一个变量即可。

注意:我将实现getValue()而不是getFace()来返回卡片的“适当”值，而不是数组的索引。

//instance variables
private String suit;
private int face;
private int value;

//constructors
public Card( String s, int f)
{
    suit = s;
    face = f;
    value = f;              // This handles 2..10
    if (f > 10) value = 10; // Face values are all 10
    if (f == 1) value = 11; // Ace. Remove if 1 and 11 should be different
}

public String toString()
{
    String s = FACES[face] + " of " + suit;
    if (face > 10 || face == 1) {
        s += " " + value;
    }
    return s;
}