我试图在Ubuntu中为C和C++程序使用CBMC有界模型检查器。我下载了gcc (4.9V)和g++ (4.9V)编译器,并通过终端安装了CBMC。
我能够验证C程序,使用以下过程不会出现任何问题:
名为.c file2.c的ΑΑ文件
int array[10];
int sum(){
unsigned i,sum;
sum=0;
for(i=0;i<10;i++)
sum+=array[i];
}终端类型:
cbmc file2.c --function sum输出:
file file2.c: Parsing
Converting
Type-checking file2
Generating GOTO Program
Adding CPROVER library
Function Pointer Removal
Partial Inlining
Generic Property Instrumentation
Starting Bounded Model Checking
Unwinding loop c::sum.0 iteration 1 file file2.c line 5 function sum thread 0
Unwinding loop c::sum.0 iteration 2 file file2.c line 5 function sum thread 0
Unwinding loop c::sum.0 iteration 3 file file2.c line 5 function sum thread 0
Unwinding loop c::sum.0 iteration 4 file file2.c line 5 function sum thread 0
Unwinding loop c::sum.0 iteration 5 file file2.c line 5 function sum thread 0
Unwinding loop c::sum.0 iteration 6 file file2.c line 5 function sum thread 0
Unwinding loop c::sum.0 iteration 7 file file2.c line 5 function sum thread 0
Unwinding loop c::sum.0 iteration 8 file file2.c line 5 function sum thread 0
Unwinding loop c::sum.0 iteration 9 file file2.c line 5 function sum thread 0
Unwinding loop c::sum.0 iteration 10 file file2.c line 5 function sum thread 0
size of program expression: 71 steps
simple slicing removed 0 assignments
Generated 0 VCC(s), 0 remaining after simplification
VERIFICATION SUCCESSFUL当我尝试执行以下.cpp文件时,会得到一个错误。
sum_num.cpp文件:
// This program adds two numbers and prints their sum.
#include <iostream>
int main()
{
int a;
int b;
int sum;
sum = a + b;
std::cout<<"The sum of "<<a<<" and "<<b<<" is "<<sum<<"\n";
return 0;
}输入终端:
cbmc sum_num.cpp --function main输出-错误:
file sum_num.cpp: Parsing
Converting
Type-checking sum_num
file /usr/include/c++/4.9/ext/type_traits.h line 172: template specialization with wrong number of arguments
CONVERSION ERROR发布于 2016-04-05 11:08:12
显然,在的时候,cbmc对模板的支持有限,并且没有涵盖它们的所有潜在用途。
在情况发生变化之前,您可以:
/usr/include/c++/4.9/ext/type_traits.h中没有这样的模板用法(4.8也有,所以是旧的)。#include<iostream>并依赖标准的C printf()函数:
#include int (){ int a;int b;int sum;sum =a+ b;printf(“%d和%d的和为%d\n",a,b,sum);返回0;}这两项建议都是这里提出的。
https://stackoverflow.com/questions/36196567
复制相似问题