简单UIPickerView误差

Question

我在myPicker.dataSource = self的行中得到了以下错误。有谁知道这是为什么，或者我能做些什么来修复它吗？

威胁1:EXC_BAD_INSTRUCTION (code=EXC_1386_INVOP，subcode=0x0)

以下是代码：

import UIKit

class ViewController: UIViewController, UIPickerViewDataSource, UIPickerViewDelegate {

    @IBOutlet var myPicker: UIPickerView!
    @IBOutlet var textFIled: UITextField!

    let pickerData = ["Mozzarella","Gorgonzola","Provolone","Brie","Maytag Blue","Sharp Cheddar","Monterrey Jack","Stilton","Gouda","Goat Cheese", "Asiago"]

    override func viewDidLoad() {
        super.viewDidLoad()
        myPicker.dataSource = self
        myPicker.delegate = self
    }

    func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int {
        return 1
    }
    func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
        return pickerData.count
    }
    func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
        return pickerData[row]
    }

    func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
        textFIled.text = pickerData[row]
    }
}

Answer 1

当您的IBOulet不正确地连接到故事板中的UIPickerView时，就会发生这种情况。删除所有连接并重新连接。

Answer 2

首先，确保myPickerView在故事板中是连接的。在故事板和ViewController中检查出口名称是否相同。

如果没有运气，请尝试通过故事板将您的故事板UIPickerView连接到委托和数据源。右击并从选择器视图拖动到视图控制器，并选择“委托”和"dataSource“。