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社区首页 >问答首页 >日历项目几乎用C语言完成

问日历项目几乎用C语言完成
EN

Stack Overflow用户
提问于 2016-03-15 17:59:29
回答 2查看 192关注 0票数 1

我正在做一个大约4天前到期的日历项目，但我一直在做这个项目，尽管我的分数会大大降低，因为我想试着去理解它。到目前为止，我已经在调试中打印出日历以及日历中正确的天数。我唯一想要修正的是，我想让每个月的第一天从正确的位置开始，所以可能是某种循环+“”，这样它就可以把4个空格循环到一个月的第一天，或者类似的东西。我还想要它，以便当我输入月份、年份和数字月份时，月份和年份将显示一个月的日历，而数字月份将显示接下来的月份。这对我来说是个很难理解的概念。帮助太大了！感谢你！我已经为这个工作了很长时间了。

​

代码语言：javascript
复制
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>

int getdaycode(int month, int year);
void printheader(int month, int year);
int getndim(int month, int year);

int main(void) {
    int  day, month, year, nummonths;
    printf("Enter Month, Year, and number of Months: ");
    if (scanf("%d %d %d", &month, &year, &nummonths) != 3
    ||  year < 0 || month < 1 || month > 12) {
        printf("invalid input\n");
        return 1;
    }

    for (int i = 0; i < nummonths; i++) {
        printheader(month, year);
        int numdays = getndim(month, year);
        int daycode = getdaycode(month, year);

        printf("%*s", daycode * 4, "");   /* print 4 spaces for each skipped day */
        for (day = 1; day <= numdays; day++) {
            printf("%3d", day);
            daycode = (daycode + 1) % 7;
            if (daycode != 0)
                printf(" ");
            else
                printf("\n");
        }
        if (daycode != 0)
            printf("\n");
        printf("\n");

        month = month + 1;
        if (month > 12) {
            month -= 12;
            year += 1;
        }
    }
    return 0;
}

int getdaycode(int month, int year)
{
	int numdays;
	{
		numdays = ((year - 1) * 365 + ((year - 1) / 4) - ((year - 1) / 100) + ((year - 1) / 400)); // how many days including exceptions

		if (((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0))		//check if leapyear
		{
			if (month == 1)							// January 
				numdays = numdays;
			if (month == 2)							// February 
				numdays = numdays + 31;
			if (month == 3)							// March 
				numdays = numdays + 28 + 31 + 1;
			if (month == 4)							// April 
				numdays = numdays + 31 + 28 + 31 + 1;
			if (month == 5)							// May 
				numdays = numdays + 30 + 31 + 28 + 31 + 1;
			if (month == 6)							// June 
				numdays = numdays + 31 + 30 + 31 + 28 + 31 + 1;
			if (month == 7)							// July 
				numdays = numdays + 30 + 31 + 30 + 31 + 28 + 31 + 1;
			if (month == 8)							// August 
				numdays = numdays + 31 + 30 + 31 + 30 + 31 + 28 + 31 + 1;
			if (month == 9)							// September 
				numdays = numdays + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31 + 1;
			if (month == 10)							// October						
				numdays = numdays + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31 + 1;
			if (month == 11)							// November
				numdays = numdays + 31 + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31 + 1;
			if (month == 12)							// December
				numdays = numdays + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31 + 1;
		}
		else
		{
			if (month == 1)							// January 
				numdays = numdays;
			if (month == 2)							// February 
				numdays = numdays + 31;
			if (month == 3)							// March 
				numdays = numdays + 28 + 31;
			if (month == 4)							// April 
				numdays = numdays + 31 + 28 + 31;
			if (month == 5)							// May 
				numdays = numdays + 30 + 31 + 28 + 31;
			if (month == 6)							// June 
				numdays = numdays + 31 + 30 + 31 + 28 + 31;
			if (month == 7)							// July 
				numdays = numdays + 30 + 31 + 30 + 31 + 28 + 31;
			if (month == 8)							// August 
				numdays = numdays + 31 + 30 + 31 + 30 + 31 + 28 + 31;
			if (month == 9)							// September 
				numdays = numdays + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31;
			if (month == 10)							// October						
				numdays = numdays + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31;
			if (month == 11)							// November
				numdays = numdays + 31 + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31;
			if (month == 12)							// December
				numdays = numdays + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + 31 + 28 + 31;
		}

	}
	int daycode = (numdays + 1) % 7;
	return daycode;
}

void printheader(int month, int year)
	{
			printf("%14d %1d\n", month, year);
			printf("Sun ");
			printf("Mon ");
			printf("Tue ");
			printf("Wed ");
			printf("Thu ");
			printf("Fri ");
			printf("Sat\n");
		}

int getndim(int month, int year)
{
	int numdays;
	if (((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0))		//check if leapyear
	{
		if (month == 1)							// January 
			numdays = 31;
		if (month == 2)							// February 
			numdays = 29;
		if (month == 3)							// March 
			numdays = 31;
		if (month == 4)							// April 
			numdays = 30;
		if (month == 5)							// May 
			numdays = 31;
		if (month == 6)							// June 
			numdays = 30;
		if (month == 7)							// July 
			numdays = 31;
		if (month == 8)							// August 
			numdays = 31;
		if (month == 9)							// September 
			numdays = 30;
		if (month == 10)							// October						
			numdays = 31;
		if (month == 11)							// November
			numdays = 30;
		if (month == 12)							// December
			numdays = 31;
	}
	else
	{
		if (month == 1)							// January 
			numdays = 31;
		if (month == 2)							// February 
			numdays = 28;
		if (month == 3)							// March 
			numdays = 31;
		if (month == 4)							// April 
			numdays = 30;
		if (month == 5)							// May 
			numdays = 31;
		if (month == 6)							// June 
			numdays = 30;
		if (month == 7)							// July 
			numdays = 31;
		if (month == 8)							// August 
			numdays = 31;
		if (month == 9)							// September 
			numdays = 30;
		if (month == 10)							// October						
			numdays = 31;
		if (month == 11)							// November
			numdays = 30;
		if (month == 12)							// December
			numdays = 31;
	}
	return numdays;
}

​

​

​

c
printf
scanf
EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2016-03-15 19:21:28

您的代码有几个问题：

  • 你对daycode的计算少了一个。
  • 您不使用daycode，而不是在main()中使用nummonths，导致所有的月份似乎都在周日开始。

以下是一个建议：

代码语言：javascript
复制
int main(void) {
    int  day, month, year, nummonths;
    printf("Enter Month, Year, and number of Months: ");
    if (scanf("%d %d %d", &month, &year, &nummonths) != 3
    ||  year <= 0 || month < 1 || month > 12) {
        printf("invalid input\n");
        return 1;
    }

    for (int i = 0; i < nummonths; i++) {
        printheader(month, year);
        int numdays = getndim(month, year);
        int daycode = getdaycode(month, year);

        printf("%*s", daycode * 4, "");   /* print 4 spaces for each skipped day */
        for (day = 1; day <= numdays; day++) {
            printf("%3d", day);
            daycode = (daycode + 1) % 7;
            if (daycode != 0)
                printf(" ");
            else
                printf("\n");
        }
        if (daycode != 0)
            printf("\n");
        printf("\n");

        month = month + 1;
        if (month > 12) {
            month -= 12;
            year += 1;
        }
    }
    return 0;
}

您还需要通过更改公式来修正getdaycode，以便从函数末尾的numdays中计算它：

代码语言：javascript
复制
            ...
        }
        int daycode = (numdays + 1) % 7;
        return daycode;
    }
}

如果您已经学习了数组，那么您的代码可以简化很多：

代码语言：javascript
复制
static int const days[12] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
static int const leapdays[12] = { 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };

int getdaycode(int month, int year) {
    int numdays = 0;
    if (year > 0) {
        // how many days in previous years including exceptions
        numdays = (year - 1) * 365 + (year - 1) / 4 - (year - 1) / 100 + (year - 1) / 400;
    }
    if (month >= 1 && month <= 12) {
        if (month > 2 && (((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0)))
            numdays += 1;  // count february 29
        for (int i = 0; i < month - 1; i++)
            numdays += days[i];
    }
    // need to offset by one so 1/1/1 falls on a Monday.
    // dates before 1753 are computed according to the
    // proleptic Gregorian calendar.
    return (numdays + 1) % 7;
}

int getndim(int month, int year) {
    if (month < 1 || month > 12)
        return 0;
    else
    if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
        return leapdays[month - 1];
    else
        return days[month - 1];
}
票数 3
EN

Stack Overflow用户

发布于 2016-03-15 19:13:32

我最近做了一些类似的事情，因为我想知道三月、四月和五月的星期二的数目。所以我写了这段代码

代码语言：javascript
复制
#include <stdio.h>

int main( void )
{
    char *monthNames[] = { "March", "April", "May" };

    printf( "Enter starting day (0-6): " );
    int day;
    if ( scanf( "%d", &day ) != 1 )
        return 1;

    day = -(day % 7);
    for ( int m = 0; m < 3; m++ ) {
        printf( "\n%s\n", monthNames[m] );
        int maxday = (m == 1) ? 30 : 31;

        while ( day < maxday ) {
            for ( int col = 0; col < 7; col++ ) {
                if ( day < 0 )
                    printf( "   " );
                else if ( day < maxday )
                    printf( " %2d", day+1 );
                day++;
            }
            printf( "\n" );
        }

        if ( day > maxday )
            day = day - maxday - 7;
        else
            day = 0;
    }
}

总的思想是变量day从-6和0之间的一个数字开始。只要day是负的，代码就会打印三个空格。当day在月份中的天数介于0和天数之间时，代码会打印一个数字。在月底，day的起始值将根据上个月的结束位置计算下一个月的起始值。

票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：

https://stackoverflow.com/questions/36018735

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