编码文件名多部分/表单-通配符9上的数据

Question

发送一个以文件名编码的捷克字符UTF-8 (kůň.txt luťoučk)的文件，该文件由RESTEasy消费。但是在java中，我总是变成US文件名(当然，这是错误的)

用于发送文件的HTML：

Select a file to upload: <br />
<form action="http://localhost/file/upload" method="post" enctype="multipart/form-data" accept-charset="UTF-8">
    <input type="file" name="file" size="50" />

    <input type="submit" value="Upload File" />
</form>

和是真正的发送：

------WebKitFormBoundaryAyBqNu6jIFHAB660
Content-Disposition: form-data; name="file"; filename="Žluťoučký kůň.txt"
Content-Type: text/plain

用于获得UTF-8编码的过滤器：

@Override
public void doFilter(ServletRequest servletRequest, ServletResponse servletResponse, FilterChain filterChain)
        throws IOException, ServletException {
    servletRequest.setCharacterEncoding("UTF-8");

 @Override
    public void filter(ContainerRequestContext requestContext) throws IOException {
        requestContext.setProperty(InputPart.DEFAULT_CONTENT_TYPE_PROPERTY, "*/*; charset=UTF-8");
        requestContext.setProperty(InputPart.DEFAULT_CHARSET_PROPERTY, "UTF-8");

读取多部分的Java代码：

 public List<CaseFile> uploadFile(MultipartFormDataInput input, long caseId) {
        MultipartFormDataOutput mdo = new MultipartFormDataOutput();
    Map<String, List<InputPart>> uploadForm = input.getFormDataMap();

    for (List<InputPart> inputParts : uploadForm.values()) {

        for (InputPart inputPart : inputParts) {
            try {

                // Retrieve headers, read the Content-Disposition header to obtain the original name of the file
                MultivaluedMap<String, String> headers = inputPart.getHeaders(); //here are all headers in US-ASCII

标题包括：

表单数据；name="file"；filename=？？lu?ou?k? k????.txt“

Answer 1

我在resteasy中使用野蝇9。上面的代码为我带来了类强制转换异常。下面的代码解决了我的问题：

        Field field = inputPart.getClass().getDeclaredField("bodyPart");
        field.setAccessible(true);
        Object bodyPart = field.get(inputPart);
        Method methodBodyPart = bodyPart.getClass().getMethod("getHeader", new Class[]{});
        Iterable iterable = (Iterable)methodBodyPart.invoke(bodyPart, new Class[]{});
        Object[] content = IteratorUtils.toArray(iterable.iterator());
        Method methodContent = content[0].getClass().getMethod("getRaw", new Class[]{});

        String[] contentDisposition = methodContent.invoke(content[0], new Class[]{}).toString().split(";");

        for (String filename : contentDisposition) {
            if ((filename.trim().startsWith("filename"))) {

                String[] name = filename.split("=");

                String finalFileName = name[1].trim().replaceAll("\"", "");
                return finalFileName;
            }
        }