从字符串中提取目录

Question

我需要提取字符串的目录，示例如下：

222.77.201.211 - - [20/Sep/2013:00:10:23 +0800] "GET /mapreduce-nextgen/hadoop-internals-mapreduce-reference/ HTTP/1.1" 200 28664 "-" "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1;)"
220.181.89.164 - - [20/Sep/2013:00:10:25 +0800] "GET /mapreduce/hadoop-capacity-scheduler HTTP/1.1" 301 390 "-" "Sogou web spider/4.0(+http://www.sogou.com/docs/help/webmasters.htm#07)"
175.44.54.185 - - [20/Sep/2013:00:10:25 +0800] "GET /mapreduce-nextgen/apache-hadoop-2-0-3-published HTTP/1.1" 301 439 "http://dongxicheng.org/mapreduce-nextgen/apache-hadoop-2-0-3-published/" "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1;)"
175.44.54.185 - - [20/Sep/2013:00:10:25 +0800] "GET /search-engine/scribe-intro/ HTTP/1.1" 200 21578 "-" "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1;)"
112.111.174.38 - - [20/Sep/2013:00:10:30 +0800] "GET /structure/segment-tree HTTP/1.1" 301 414 "http://dongxicheng.org/structure/segment-tree/" "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1;)"
112.111.174.38 - - [20/Sep/2013:00:10:30 +0800] "GET /structure/segment-tree HTTP/1.1" 301 414 "-" "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1;)"
222.77.201.211 - - [20/Sep/2013:00:10:31 +0800] "GET /mapreduce-nextgen/apache-hadoop-2-0-3-published/ HTTP/1.1" 200 23438 "http://dongxicheng.org/mapreduce-nextgen/apache-hadoop-2-0-3-published/" "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1;)"

预期产出将是：

• /mapreduce-nextgen/hadoop-internals-mapreduce-reference/
• /mapreduce/hadoop-capacity-scheduler
• /mapreduce-nextgen/apache-hadoop-2-0-3-published
• 等等。

我认为可能需要一个正则表达式。提前感谢！

Answer 1

好的，上面的答案是有效的，而且可能更好，但是我用.indexOf()做了。文本中的第一行阅读并不是我在Hadoop处理它时是如何做到的，而是为了简洁起见。

Text value = "112.111.186.210 - - [20/Sep/2013:00:10:22 +0800] \"GET /structure/segment-tree HTTP/1.1\" 301 414 \"-\" \"Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1;)\"","GET ", " HTTP"


     int idx = value.toString().indexOf("GET");
     int idy = value.toString().indexOf("HTTP/1");
     ip.set(value.toString().substring(idx, idy).trim());

Answer 2

如果总是在GET和HTTP之间，最简单的Regex应该是这样的：

GET (.*?) HTTP

证明：Regex101

在Java中，代码应该如下所示：

Pattern p = Pattern.compile("GET (.*?) HTTP");
Matcher m = p.matcher(string);

编辑:不要忘记将\放在字符串中的每个"之前，否则它将被解释为字符串的结尾。

String str = "222.77.201.211 - - [20/Sep/2013:00:10:23 +0800] \"GET /mapreduce-nextgen/hadoop-internals-mapreduce-reference/ HTTP/1.1\" 200 28664 \"-\" \"Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1;)\"";

上面的字符串的输出将是/mapreduce-nextgen/hadoop-internals-mapreduce-reference/。

Answer 3

String toInspect = "112.111.186.210 - - [20/Sep/2013:00:10:22 +0800] \"GET /structure/segment-tree HTTP/1.1\" 301 414 \"-\" \"Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1;)\"";
String directory = StringUtils.substringBetween(toInspect ,"GET ", " HTTP");