如何在iOS 9中打开电话拨号程序？

Question

我找到了解决方案，需要在info.plist中添加一些代码。我是这样做的：

<key>LSApplicationQueriesSchemes</key>
<array>
    <string>tel</string>
</array>

还是没有帮助。我知道这个错误：

-canOpenURL: failed："tel://4806501708“--错误：”此应用程序不允许查询方案tel“

我打开拨号程序的代码：

NSString *phoneNumber = [@"tel://" stringByAppendingString:lblVenPhoneValue.text];
if ([UIApplication.sharedApplication canOpenURL:[NSURL URLWithString:phoneNumber]]) {
        [UIApplication.sharedApplication openURL:[NSURL URLWithString:phoneNumber]];

我该怎么办？

提前谢谢

Answer 1

你在设备上测试这个吗？，因为这在模拟器上不起作用。设备也应该有sim卡。

确认以上内容后，尝试如下

在info.plist中

<key>LSApplicationQueriesSchemes</key>
<array>
<string>tel</string>
<string>telprompt</string>
</array>

哪里要开电话拨号机？

 [[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:@"tel:%@",@"digits"]]]; 

或

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:@"telprompt:%@",@"digits"]]];

Answer 2

只要把"//“从”tel://“中删除就可以了

NSString *phoneNumber = [@"tel:" stringByAppendingString:lblVenPhoneValue.text];
if ([UIApplication.sharedApplication canOpenURL:[NSURL URLWithString:phoneNumber]]) {
        [UIApplication.sharedApplication openURL:[NSURL URLWithString:phoneNumber]];

为了获得更好的检查，您可以使用

if([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:[NSString stringWithFormat:phoneNumber]]])
{
  CTTelephonyNetworkInfo *networkInfo = [CTTelephonyNetworkInfo new];
  CTCarrier *carrier = [networkInfo subscriberCellularProvider];
  NSString *_code = [carrier mobileNetworkCode];
  if(_code)
  {
    [[UIApplication sharedApplication] openURL:phoneNumber]];
  }
  else
  {
    UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"no_sim" message:@"" delegate:nil cancelButtonTitle:@"ok" otherButtonTitles:nil, nil];
    [alert show];
  }
}
else
{
  UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"alert" message:@"alert_device_not_support" delegate:nil cancelButtonTitle:@"ok" otherButtonTitles:nil, nil];
  [alert show];
}

Answer 3

对于SWIFT4.0，请使用此方法(确保您不在模拟器上)

        let cleanPhoneNumber = phone.components(separatedBy: CharacterSet.decimalDigits.inverted).joined(separator: "")
        let urlString:String = "tel://\(cleanPhoneNumber)"

        if let phoneCallURL = URL(string: urlString) {
            if (UIApplication.shared.canOpenURL(phoneCallURL)) {
                UIApplication.shared.open(phoneCallURL, options: [:], completionHandler: nil)
            }
        }