Python-2:将文本文件中的行分配给变量

Question

我目前正试图从一个uni项目的文本文件中为竞赛制作一个记分板。

每个竞争对手都有一个competitor_no、competitor_name和3分，它们都显示在文本文件中的不同行上(因此每个竞争者的数据需要5行)，例如：

1

伊莉莎·兰森

9.19

11.79

21.66

2

希希·杜兰特

17.03

7.02

17.72

我需要能把3分加起来才能得到总分，我有50个竞争对手，需要对他们进行比较，才能显示出前3名选手的号码、名字和总分。是否有将行值赋值给变量的方法？

显然，我需要一次比较5行，以获得每个竞争对手所需的信息，并处理数据--这是我在程序中设置的代码。

 file = open('veggies_2014.dat')

    for line in file:

            first_place = []
            second_place = []
            third_place = []

            a = 1 
            b = 2
            c = 3
            d = 4
            e = 5

            if line == a:
                    competitor_no = line
            elif line == b:
                    competitor_name = line
            elif line == c:
                    cucumber = line
            elif line == d:
                    carrot = line
            elif line == e:
                    runner_bean = line

            a += 5
            b += 5
            c += 5
            d += 5
            e += 5

            score = float(cucumber) + float(carrot) + float(runner_bean)
            print(score)

            if score > first:
                    first = score
                    first_place.append(competitor_no)
                    first_place.append(competitor_name)
                    first_place.append(score)
            elif score > second:
                    second = score
                    second_place.append(competitor_no)
                    second_place.append(competitor_name)
                    second_place.append(score)
            elif score > third:
                    third = score
                    third_place.append(competitor_no)
                    third_place.append(competitor_name)
                    third_place.append(score)

    file.close()

    print (first_place)
    print (second_place)
    print (third_place)  

当我只是在处理一个包含数字的文件时，我可以得到分数if语句，但是必须包含这个名字似乎是我的绊脚石。

有什么建议吗？

Answer 1

由于您知道信息出现在文件中的顺序，所以尝试一次以5行的块读取该文件，然后相应地处理它。在下面的实现中，我将信息存储在2D列表中，然后按分数进行排序，从而获得最高的分数。

data = []
count = 1
with open("veggies_2014.dat") as f:
    line = f.readline()
    while line and int(line) == count:
        score = 0
        entry = []
        entry.append(f.readline())   #read line with c_name
        for i in range(3):
            score += float(f.readline())     #add scores
        entry.append(score)
        data.append(entry)
        line = f.readline()
        count += 1

print(data)
data = sorted(data, key = lambda l:l[1], reverse = True)
print()
print(data)

Answer 2

你可以做这样的事情(没有测试--但你明白了)：基本上，每次计数到0，你就把分数保存在一个以人的名字为键的personDict中.

count = 0
c1_no = None;
personDict = dict()
with open("veggies_2014.dat") as f:
    score = 0
    for line in f:
        if count%5==0:
          if c1_no:
              personDict[c1_no] = score
          c1_no = line
          score = 0
       elif count%5 == 1:
          c1_name = line
       elif count%5 in (2,3,4):
           score += float(line)
       count += 1

 #now do whatever you want with the personDict..you will have something like {Emily:10} assuming Emily's scores were 2,3,5 etc

Answer 3

以下是我想出的：

file_content = '''1
Eliza Ianson
9.19
11.79
21.66
2
Cece Durant
17.03
7.02
17.72
3
Foo Bar
10
9.5
11.2
4
Superman
7.9
12.15
9.75
'''


def chunks(l, n):
    """Yield successive n-sized chunks from l."""
    """ from http://stackoverflow.com/questions/312443/how-do-you-split-a-list-into-evenly-sized-chunks-in-python """
    for i in xrange(0, len(l), n):
        yield l[i:i+n]


users = []
for user_data in chunks(file_content.splitlines(), 5):
    user_id = int(user_data[0])
    user_name = user_data[1]
    scores = list(map(float, user_data[2:]))
    overall_score = sum(scores)

    users.append(dict(
        user_id=user_id,
        user_name=user_name,
        scores=scores,
        overall_score=overall_score
    ))


top_3 = sorted(users, key=lambda x: x['overall_score'], reverse=True)[:3]