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社区首页 >问答首页 >UnregisterListener不适用于PROXIMITY_SCREEN_OFF_WAKE_LOCK

UnregisterListener不适用于PROXIMITY_SCREEN_OFF_WAKE_LOCK
EN

Stack Overflow用户
提问于 2016-03-03 08:42:07
回答 3查看 1.7K关注 0票数 7

我有这个密码

代码语言:javascript
复制
public class MainActivity extends AppCompatActivity implements SensorEventListener {

    private SensorManager mSensorManager;
    private Sensor mProximity;
    private PowerManager mPowerManager;
    private PowerManager.WakeLock mWakeLock;


    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);


        mSensorManager = (SensorManager) getSystemService(Context.SENSOR_SERVICE);
        mProximity = mSensorManager.getDefaultSensor(Sensor.TYPE_PROXIMITY);

        mPowerManager = (PowerManager) getSystemService(Context.POWER_SERVICE);
    }

    @Override
    protected void onResume() {
        super.onResume();
        mSensorManager.registerListener(this, mProximity, SensorManager.SENSOR_DELAY_NORMAL);
    }

    @Override
    protected void onPause() {
        super.onPause();
        mSensorManager.unregisterListener(this);
    }

    @Override
    public void onSensorChanged(SensorEvent event) {
        if (event.sensor.getType() == Sensor.TYPE_PROXIMITY) {
            if (event.values[0] == 0) {
                //near
                Toast.makeText(getApplicationContext(), "near", Toast.LENGTH_SHORT).show();
                turnOffScreen();

            } else {
                //far
                Toast.makeText(getApplicationContext(), "far", Toast.LENGTH_SHORT).show();
                turnOnScreen();
            }
        }
    }

    @Override
    public void onAccuracyChanged(Sensor sensor, int accuracy) {

    }


    public void turnOffScreen() {

            mWakeLock = mPowerManager.newWakeLock(PowerManager.PROXIMITY_SCREEN_OFF_WAKE_LOCK, "tag");
            mWakeLock.acquire();

    }

    public void turnOnScreen() {

            mWakeLock = mPowerManager.newWakeLock(PowerManager.SCREEN_BRIGHT_WAKE_LOCK | PowerManager.ACQUIRE_CAUSES_WAKEUP, "tag");
            mWakeLock.acquire();
    }

}

当应用程序在睡觉或进入其他活动时,传感器仍能工作。有什么想法吗?

EN

回答 3

Stack Overflow用户

回答已采纳

发布于 2016-03-08 12:07:14

我采用了其他的方法来解决这个问题,因为没有人知道如何解决这个问题,所以对于这些代码,我不需要使用SensorManager。现在我使用两个功能启动和停止传感器,我认为是唯一的解决方案。

代码语言:javascript
复制
import android.content.Context;
import android.os.PowerManager;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Toast;

public class MainActivity extends AppCompatActivity {

    private PowerManager mPowerManager;
    private PowerManager.WakeLock mWakeLock;

    private static final String TAG = "MainActivity";

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        mPowerManager = (PowerManager) getSystemService(Context.POWER_SERVICE);
    }

    public void activateSensor(View v) {
        Toast.makeText(MainActivity.this, "Proximity On", Toast.LENGTH_LONG).show();
        if (mWakeLock == null) {
            mWakeLock = mPowerManager.newWakeLock(PowerManager.PROXIMITY_SCREEN_OFF_WAKE_LOCK, "incall");
        }
        if (!mWakeLock.isHeld()) {
            Log.d(TAG, "New call active : acquiring incall (CPU only) wake lock");
            mWakeLock.acquire();
        } else {
            Log.d(TAG, "New call active while incall (CPU only) wake lock already active");
        }
    }

    public void deactivateSensor(View v) {
        Toast.makeText(MainActivity.this, "Proximity Off", Toast.LENGTH_LONG).show();
        if (mWakeLock != null && mWakeLock.isHeld()) {
            mWakeLock.release();
            Log.d(TAG, "Last call ended: releasing incall (CPU only) wake lock");
        } else {
            Log.d(TAG, "Last call ended: no incall (CPU only) wake lock were held");
        }
    }

}

这是我的activity_main.xml

代码语言:javascript
复制
    <?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:paddingBottom="@dimen/activity_vertical_margin"
    android:paddingLeft="@dimen/activity_horizontal_margin"
    android:paddingRight="@dimen/activity_horizontal_margin"
    android:paddingTop="@dimen/activity_vertical_margin"
    tools:context="com.example.javier.proximitysensor.MainActivity">

    <Button
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:layout_above="@+id/activity_main_turn_on_screen"
        android:onClick="activateSensor"
        android:text="@string/activity_main_activate_sensor" />

    <Button
        android:id="@+id/activity_main_turn_on_screen"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:layout_alignParentBottom="true"
        android:onClick="deactivateSensor"
        android:text="@string/activity_main_deactivate_sensor" />
</RelativeLayout>

谢谢..。

此外,您还可以在GitHub中检查此示例

票数 2
EN

Stack Overflow用户

发布于 2016-03-12 09:10:06

在初始代码中,您还没有正确地处理释放唤醒锁的问题。当您的活动在onStop中时,请注销侦听器并释放所持有的唤醒锁。

票数 0
EN

Stack Overflow用户

发布于 2017-04-12 03:38:32

使用函数wakeLock.setReferenceCounted(false)。我用过它,而且很管用。

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/35767115

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