import subprocess
child = subprocess.Popen(['python', 'simple.py'], stdin=subprocess.PIPE)
child.communicate('Alice')我知道您可以通过通信与已执行的脚本进行通信,如何检查脚本“simple.py”是否要求用户输入?
simple.py可以要求5-10个用户输入,所以简单地硬编码communicate是不够的。
编辑:希望在脚本运行时解析stdout并与脚本进行通信。
while True:
if child.get_stdout() == '?':
# send user input发布于 2016-03-02 15:44:31
一个简单的例子:
simple.py:
i = raw_input("what is your name\n")
print(i)
j = raw_input("What is your age\n")
print(j)读和写:
import subprocess
child = subprocess.Popen(['python2', 'simple.py'], stdin=subprocess.PIPE, stdout=subprocess.PIPE)
for line in iter(child.stdout.readline, ""):
print(line)
if "name" in line:
child.stdin.write("foo\n")
elif "age" in line:
child.stdin.write("100\n")输出:
what is your name
foo
What is your age
100https://stackoverflow.com/questions/35751295
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