自动完成searchBar

Question

我正试图在我的searchBar应用程序中实现一个iOS。我正在从应用程序中搜索国家和城市。国家和城市的名字来自数据库。我的代码中没有几个问题。

首先，现在我的代码成功地搜索了这个城市，但它并不是搜索国家名称，我也不知道如何搜索国家名称。

    func updateSearchResultsForSearchController(searchController: UISearchController) {

                let searchWord = searchController.searchBar.text!

                getCountriesNamesFromServer(searchWord)

                self.filteredKeys.removeAll()

                for (key, value) in self.dict {
                    let valueContainsSearchWord: Bool = (((value as? NSDictionary)?["City"] as? NSDictionary)?["name"] as? String)?.uppercaseString.containsString(searchWord.uppercaseString) ?? false
                    if valueContainsSearchWord {
                        self.filteredKeys.append(key as! String)
                    }
                }

                self.tableView.reloadData()
            }

第二个问题是，我想得到选择的国家和城市的ids以及用户选择的应用程序。关于您的信息，我也从服务器获得了I。

这是我的完整代码

class CountryTableViewController: UITableViewController, UISearchResultsUpdating {

    var dict = NSDictionary()
    var filteredKeys = [String]()

    var resultSearchController = UISearchController()

    var newTableData = [String]()

    override func viewDidLoad() {
        super.viewDidLoad()

        self.resultSearchController = ({

            let controller  = UISearchController(searchResultsController: nil)
            controller.searchResultsUpdater = self
            controller.dimsBackgroundDuringPresentation = false
            controller.searchBar.sizeToFit()
            self.tableView.tableHeaderView = controller.searchBar
            return controller


        })()

        self.tableView.reloadData()
    }

    override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {

        if (self.resultSearchController.active) {

            return self.filteredKeys.count
        } else {

            return dict.count
        }

    }

    override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {

        let cell = tableView.dequeueReusableCellWithIdentifier("cell", forIndexPath: indexPath) as! CountryTableViewCell

        if(self.resultSearchController.active){

            let key = self.filteredKeys[indexPath.row]

            let dictionary = self.dict[key] as! NSDictionary

            if

                let cityName = (((self.dict["\(indexPath.row)"] as?NSDictionary)!["City"] as?NSDictionary)!["name"] as?NSString),

               let stateName  = (((self.dict["\(indexPath.row)"] as?NSDictionary)!["State"] as? NSDictionary)!["name"] as? NSString),

                 let shortName  = (((self.dict["\(indexPath.row)"] as?NSDictionary)!["Country"] as? NSDictionary)!["short_name"] as? NSString)

            {
                cell.stateNameLabel.text = stateName as String
                cell.cityNameLabel.text = cityName as String
                 cell.shortNameLabel.text = shortName as String
            }


                      return cell

        }else{
            if let cityName = (((self.dict["\(indexPath.row)"] as?NSDictionary)!["City"] as?NSDictionary)!["name"] as?NSString){
            cell.cityNameLabel.text = cityName as String
            }
            return cell
        }



    }

    func updateSearchResultsForSearchController(searchController: UISearchController) {

        let searchWord = searchController.searchBar.text!

        getCountriesNamesFromServer(searchWord)

        self.filteredKeys.removeAll()

        for (key, value) in self.dict {
            let valueContainsSearchWord: Bool = (((value as? NSDictionary)?["City"] as? NSDictionary)?["name"] as? String)?.uppercaseString.containsString(searchWord.uppercaseString) ?? false
            if valueContainsSearchWord {
                self.filteredKeys.append(key as! String)
            }
        }

        self.tableView.reloadData()
    }




    func getCountriesNamesFromServer(searchWord:String){


        let url:String = "http://localhost"
        let params = ["keyword":searchWord]



        ServerRequest.postToServer(url, params: params) { result, error in

            if let result = result {
                print("result is\(result)")

                self.dict = result

            }
        }

    }

}

字典结构：

{
    0 =     {
        City =         {
            code = 10409;
            "country_id" = 244;
            id = 8727;
            iso = "ZA-05";
            lat = "-32.7833000";
            longi = "26.8333000";
            name = Alice;
            "state_id" = 4379;
        };
        Country =         {
            id = 244;
            name = "South Africa";
            "short_name" = ZA;
        };
        State =         {
            "country_id" = 244;
            id = 4379;
            name = "Eastern Cape";
        };
    };

Answer 1

您只是在搜索["City"]键，应该添加["Country"]键。

for (key, value) in self.dict {

        let valueContainsCity: Bool = (((value as? NSDictionary)?["City"] as? NSDictionary)?["name"] as? String)?.uppercaseString.containsString(searchWord.uppercaseString) ?? false

        let valueContainsCountry: Bool = (((value as? NSDictionary)?["Country"] as? NSDictionary)?["name"] as? String)?.uppercaseString.containsString(searchWord.uppercaseString) ?? false

        if valueContainsCity || valueContainsCountry{ self.filteredKeys.append(key as! String) }

    }

uppercaseString --你的城市和国家的名字在uppercaseString里吗？如果不做lowerCaseString

这会给你城市身份证和乡村身份证。

(((self.dict["\(indexPath.row)"] as?NSDictionary)!["City"] as?NSDictionary)!["id"] as?NSString)
(((self.dict["\(indexPath.row)"] as?NSDictionary)!["Country"] as?NSDictionary)!["id"] as?NSString)