Apache在尝试创建zNodes时未实现错误

Question

我正试图将Apache管理器与一个被移植的动物园管理员实例一起使用，无论我如何尝试连接，我总是以一个

org.apache.zookeeper.KeeperException$UnimplementedException: KeeperErrorCode =未实现的.

错误。我试着把文档弄清楚了，但我什么也没得到。我已经登录到动物园管理员CLI并确保端口号是正确的：

snerd@powerglove:~$ docker ps CONTAINER ID        IMAGE               COMMAND                CREATED             STATUS              PORTS   NAMES 31f1093495ba        compose_zookeeper   "/opt/zookeeper/bin/   3 weeks ago         Up About a minute   0.0.0.0:32770->2181/tcp,
0.0.0.0:32769->2888/tcp, 0.0.0.0:32768->3888/tcp   zookeeper

下面是我试图使用的代码：

public class App {
    public static void main( String[] args ) {
        CuratorFramework client = CuratorFrameworkFactory.newClient("0.0.0.0:32770", new RetryUntilElapsed(3000, 1000));
        client.start();

            try {
                client.create().forPath("/larry-smells/foop", "tuna?".getBytes());
            } catch (Exception e) {
                System.out.println(e.toString());
            }

    }
}

据我从策展人入门页面中可以看出，这应该是可行的。我遗漏了什么？

edit1刚刚发现，我可以从动物园管理员的集合中提取数据：

System.out.println(new String(curatorFramework.getData().forPath("/larry-smells"))); 

但是create命令仍然在爆炸。

edit2

错误的堆栈跟踪：

org.apache.zookeeper.KeeperException$UnimplementedException: KeeperErrorCode =未实现的/larry-嗅觉/foop at org.apache.zookeeper.KeeperException.create(KeeperException.java:103) at org.apache.zookeeper.KeeperException.create(KeeperException.java:51) at org.apache.zookeeper.ZooKeeper.create(ZooKeeper.java:1297) at org.apache.curator.framework.imps.CreateBuilderImpl$17.call(CreateBuilderImpl.java:1040) at org.apache.curator.framework.imps.CreateBuilderImpl$17.call(CreateBuilderImpl.org.apache.curator.connection.StandardConnectionHandlingPolicy.callWithRetry(StandardConnectionHandlingPolicy.java:67) at org.apache.curator.RetryLoop.callWithRetry(RetryLoop.java:99) at org.apache.curator.framework.imps.CreateBuilderImpl.pathInForeground(CreateBuilderImpl.java:1020) at org.apache.curator.framework.imps.CreateBuilderImpl.protectedPathInForeground(CreateBuilderImpl.java:501) at org.apache.curator.framework.imps.CreateBuilderImpl.forPath(CreateBuilderImpl.java:491) atorg.apache.curator.framework.imps.CreateBuilderImpl$4.forPath(CreateBuilderImpl.java:367) at org.apache.curator.framework.imps.CreateBuilderImpl$4.forPath(CreateBuilderImpl.java:309) at com.mycompany.app.App.main(App.java:35)

Answer 1

编辑:很明显，如果你用错了馆长和动物园管理员的组合，这个错误就会发生。来自curator.apache.org：

馆长2.x.x -兼容ZooKeeper 3.4.x和ZooKeeper 3.5.x 策展人3.x.x只与ZooKeeper 3.5.x兼容，并包括对新特性(如动态重新配置等)的支持。

很难用错误代码而不是堆栈跟踪来确定您的问题，但我建议您进行一些改进，以使应用程序更加稳定：

public class App {
    public static void main( String[] args ) {
        CuratorFramework client = CuratorFrameworkFactory.newClient("0.0.0.0:32770", new RetryUntilElapsed(3000, 1000));
        client.start();

        try {
            //make sure you're connected to zookeeper.
            client.blockUntilConnected();

            //Make sure the parents are created.
            client.create().creatingParentsIfNeeded().forPath("/larry-smells/foop", "tuna?".getBytes());
        } catch (Exception e) {
            System.out.println(e.toString());
            }

    }
}

Answer 2

我也遇到了类似的异常，我使用了下面的依赖项，这些依赖项是兼容的，并帮助我解决异常。

    <dependency>
        <groupId>org.apache.zookeeper</groupId>
        <artifactId>zookeeper</artifactId>
        <version>3.4.6</version>
    </dependency>

    <dependency>
        <groupId>org.apache.curator</groupId>
        <artifactId>curator-framework</artifactId>
        <version>4.0.1</version>
    </dependency>

    <dependency>
        <groupId>org.apache.curator</groupId>
        <artifactId>curator-x-discovery</artifactId>
        <version>4.0.1</version>
    </dependency>

Answer 3

我也有同样的问题。

我试着在练习6上使用inTransaction ()，如这里所解释的：http://www.programcreek.com/java-api-examples/index.php?api=org.apache.curator.framework.CuratorFramework，并且似乎有效。

client.inTransaction ().create().forPath("/larry-smells/foop", "tuna?".getBytes()).and ().commit ();