生成图的代码如下所示:
var allVenues = [];
var seriesData = [];
var callGraph = function () {
var where = jQuery('#hdnVal').val();
jQuery.ajax({
url: "PopulateTable",
type: 'GET',
data: {
'where': where
},
dataType: "json",
async: false,
success: function (responseJson) {
if (responseJson != null) {
jQuery.each(responseJson, function (key, value) {
jQuery('#hdnVal').val(value['date']);
});
allVenues.push(responseJson);
}
}
});
var length = 0;
var length1 = 0;
var dataXY = [];
var dataX = [];
length = allVenues.length;
for (var i = 0; i < length; i++) {
length1 = allVenues[i].length;
for (var j = 0; j < length1; j++) {
dataX.push([returnTimestamp(allVenues[i][j].date), returnDate(allVenues[i][j].date)]);
dataXY.push({x: returnTimestamp(allVenues[i][j].date), y: allVenues[i][j].price});
}
}
seriesData = [dataXY];
} ;
callGraph() ;
var palette = new Rickshaw.Color.Palette({scheme: 'classic9'});
var graph = new Rickshaw.Graph({
element: document.getElementById("chart"),
width: 900,
height: 500,
renderer: 'area',
stroke: true,
preserve: true,
series: [
{
color: palette.color(),
data: seriesData[0],
name: 'Price'
}
]
});
graph.render();
setInterval(function () {
callGraph();
graph.series.addData(seriesData);
graph.render();
}, 5000);在这段代码中,我的"seriesData“数组正在更新,但图形没有更新。生成的json数组在页面加载时对图很好,但是当我应用间隔时,图就不更新了。
发布于 2016-02-27 14:51:21
在没有像样的Rickshaw文档,也没有异步更新的例子的情况下,很难说什么会起作用,什么不起作用。
似乎没有必要维护allVenues数组,除非您希望在每次更新时从头开始重建图形。添加到系列数据并调用.render()就足够了。
你可能想要这样的东西:
(function() { // IIFE to isolate from the Global name space, if not otherwise wrapped.
var jqXHR;
var errors = {
count = 0,
threshold: 10 // number of consecutive error after which the update cycle should die
}
var palette = new Rickshaw.Color.Palette({ scheme: 'classic9' });
var lastDate = jQuery('#hdnVal').val();
var seriesData = []; // <<<<<<<<<<<< add
var graph = new Rickshaw.Graph({
element: document.getElementById('chart'),
width: 900,
height: 500,
renderer: 'area',
stroke: true,
preserve: true,
series: [{
color: palette.color(),
data: seriesData, // <<<<<<<<<<<< change
name: 'Price'
}];
});
var callGraph = function (val) {
if(jqXHR) {
// In case previous ajax has not responded.
jqXHR.abort(); // Abort previous ajax and force its error handler to fire.
return; // Allow the error handler to report the abort error then retry/die.
}
jqXHR = jQuery.ajax({
url: "PopulateTable",
type: 'GET',
data: { 'where': val },
dataType: "json"
}).then(function (responseJson) { // ajax success handler
if (responseJson) {
// Here's the major guess!
// ***** start: delete *****
// graph.series.addData(responseJson.map(function(item) {
// lastDate = item.date;
// return { x: returnTimestamp(item.date), y: item.price };
// }));
// ***** end: delete *****
// ***** start: add *****
responseJson.forEach(function(item) {
lastDate = item.date;
seriesData.push({ x: returnTimestamp(item.date), y: item.price });
});
// ***** end: add *****
}
graph.render();
errors.count = 0; //reset errorCount
setTimeout(function() {
callGraph(lastDate);
}, 5000);
}, function(jqXHR, textStatus, errorThrown) { // ajax error handler
errors.count += 1;
console.log("callGraph()", textStatus, "errorCount: " + errorCount);
if(error.count < errors.threshold) {
setTimeout(function() {
callGraph(lastDate); // retry with same lastDate as previous ajax call.
}, 5000);
} else {
// Allow the update cycle to die
console.log("callGraph() errorTheshold reached");
}
});
};
callGraph(lastDate);
})();注意,由于AJAX的异步性,在AJAX成功处理程序中更新图形并刺激更新周期的下一阶段。setTimeout()被用来代替setInterval(),而setInterval()在扼杀循环时更麻烦。
如果它仍然不能工作,那么graph.series.addData(...)部分可能是错误的。它可能只需要调试,但也可以尝试以下两种建议-- https://stackoverflow.com/a/19126145/3478010
https://stackoverflow.com/questions/35666135
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