(httplog)-static:启用-static的假android

Question

我正在开发安卓应用程序，并在三星J7上运行。问题是，在运行该应用程序时，它会显示错误"( httplog )-static: it启用假“--是否有任何方法可以启用httplog或另一种解决此问题的方法。如果在程序上想要启用该功能，如何实现？

private void tryLogin(String log, String pass) {


            HttpURLConnection connection;
               OutputStreamWriter request = null;

                    URL url = null;   
                    String response = null;         
                    String parameters = "="+log+"&="+pass;   

                    try
                    {
                         url = new URL("http://209.68.26.95/anglertechnologieseit/lc_webservice/webservice.php?Case=loginCheck");
                        connection = (HttpURLConnection) url.openConnection();
                        connection.setDoOutput(true);
                        connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
                        connection.setRequestMethod("POST");    

                        request = new OutputStreamWriter(connection.getOutputStream());
                        request.write(parameters);
                        request.flush();
                        request.close();            
                        String line = "";               
                        InputStreamReader isr = new InputStreamReader(connection.getInputStream());
                        BufferedReader reader = new BufferedReader(isr);
                        StringBuilder sb = new StringBuilder();
                        while ((line = reader.readLine()) != null)
                        {
                            sb.append(line + "\n");
                        }
                       stored in response variable.                
                        response = sb.toString();

                    Toast.makeText(this,"Message from Server: \n"+ response, 0).show();             

                        System.out.println("Message from Serverrrrrrrrrrrr     :"+response);
                        isr.close();
                        reader.close();

                    }
                    catch(IOException e)
                    {
                        System.out.println("eeerrrrooorrr"+e);
                    }

        }

​

​

Answer 1

我认为这与其说是错误，不如说是警告。如果您被这些消息垃圾邮件，您可以停用这种特定类型的错误(还有其他问题的堆栈溢出)。

我最初认为这是一个错误，因为我没有在我的服务器上接收任何数据。

我的错误是“守则”可能不起作用。(忘记请求响应代码)此代码可能会工作：

try { System.out.println("HTTP Upload");
        URL Singin_url = new URL("http://192.168.0.157:80");
        HttpURLConnection client = (HttpURLConnection)          
        Singin_url.openConnection();
        client.setRequestMethod("POST");
        client.setDoOutput(true);
        client.setDoInput(true);
        client.setConnectTimeout(10000); // 5 sec
        client.setReadTimeout(10000);

        OutputStream out = new BufferedOutputStream(client.getOutputStream());
        BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(out, "UTF-8"));
        String data = "POST_FROM_MOBILE";
        writer.write(data);
        writer.flush();
        writer.close();
        out.close();
        Log.e("E", String.valueOf(client.getResponseCode()));
    }catch(MalformedURLException error) {
        Log.e("Error","Wrong URL");
    }
    catch(SocketTimeoutException error) {
        Log.e("Error","Timeout");

    }
    catch (IOException error) {
        Log.e("Error","IOException Error");
    }

提示:使用调试器模式进行调试比较容易，因为您将看到更多的错误