如何改进清理嵌套对象方法以同时删除空对象

Question

需要改进清理嵌套对象的方法以删除空对象

​

const sanitizeNestedObject = obj => JSON.parse(JSON.stringify(obj), (key, value) => {
    if (value === null || value === "" || value === [] || value === {}) return undefined
    return value
})

​

清洗后的输出

{"expressions":[{
"hasSchemaTag":{"schemaTag":"Hardware"}},
{"hasAttribute":{"attribute":"serialNumber"}},{},{},
{"hasAnySchemaTags":{"schemaTags":["UCSFanModule","UCSMemoryArray"]}},{},{}
]}

清洗后的预期输出

{"expressions":[{
"hasSchemaTag":{"schemaTag":"Hardware"}},
{"hasAttribute":{"attribute":"serialNumber"}},
{"hasAnySchemaTags":{"schemaTags":["UCSFanModule","UCSMemoryArray"]}}
]}

Answer 1

只需检查对象是否有键(将涵盖数组和对象)。如果不是，就修剪掉：

const sanitizeNestedObject = obj => JSON.parse(JSON.stringify(obj), (key, value) => {
  if (value === null || value === "" || (typeof value === 'object' && !Object.keys(value).length)) return undefined
  return value
})

当然，您可以将该函数缩短为：

const sanitizeNestedObject = obj => JSON.parse(JSON.stringify(obj), (key, value) => {
  return (value === null || value === "" || (typeof value === 'object' && !Object.keys(value).length) ? undefined : value)
})

结果：

{"expressions":[{"hasSchemaTag":{"schemaTag":"Hardware"}},{"hasAttribute":{"attribute":"serialNumber"}},{"hasAnySchemaTags":{"schemaTags":["UCSFanModule","UCSMemoryArray"]}}]}

为了安全起见，我还检查了其他值：

这(请注意数字、字符串和空数组)：

{"expressions":[{"hasSchemaTag":{"schemaTag":"Hardware"}},{"hasAttribute":{"attribute":"serialNumber"}},{},{},[],[],["a","b","",18,0],{"hasAnySchemaTags":{"schemaTags":["UCSFanModule","UCSMemoryArray"]}},{},{}]}

深入了解以下内容：

{"expressions":[{"hasSchemaTag":{"schemaTag":"Hardware"}},{"hasAttribute":{"attribute":"serialNumber"}},["a","b",18,0],{"hasAnySchemaTags":{"schemaTags":["UCSFanModule","UCSMemoryArray"]}}]}

Answer 2

在obj上使用Remove empty objects from an object的答案之一，然后再将其放入JSON.stringify()。注意改变对象！