我想通过(client、prop1、prop2)对每个唯一的行集进行状态求和。smth类: DISTINCT(client,prop1,prop2)
这是我的桌子
client | prop1 | prop2 | status
----------------------------------
name1 | pr100 | pr310 | OK
name1 | pr100 | pr310 | error
name1 | pr100 | pr310 | OK
name1 | pr100 | pr310 | OK
name2 | pr255 | pr320 | OK
name2 | pr255 | pr320 | OK
name2 | pr255 | pr320 | error
name2 | pr400 | pr320 | error
name3 | pr400 | pr500 | OK
name3 | pr400 | pr500 | OK我试着得到这个:
client | prop1 | prop2 | OK | error
----------------------------------
name1 | pr100 | pr310 | 3 | 1
name2 | pr255 | pr320 | 2 | 1
name2 | pr400 | pr320 | 0 | 1
name3 | pr400 | pr500 | 2 | 0请帮帮忙
发布于 2016-02-17 11:52:18
这是一个聚合,而不是一个select distinct
select client, prop1, prop2,
sum(status = 'OK') as ok, sum(status = 'error') as error
from t
group by client, prop1, prop2;https://stackoverflow.com/questions/35455893
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