我试图编译我的程序并使其可执行,但每次我试图打印它时都会说:“在当前的上下文中,没有符号”郁金香“。”
这是我的代码:
#include <stdlib.h>
#include <stdio.h>
int main() {
unsigned long *daffodil = (unsigned long *) malloc(sizeof(unsigned long));
if (daffodil == (unsigned long *) NULL)
exit(EXIT_FAILURE);
*daffodil = 170;
unsigned long *tulip = daffodil;
unsigned long *carnation = (unsigned long *) malloc(sizeof(unsigned long));
if (carnation == (unsigned long *) NULL)
exit(EXIT_FAILURE);
*carnation = 995;
unsigned long *lily = tulip;
unsigned long crocus = 953;
unsigned long *zinnia = &crocus;
(void) printf("Registering daffodil: %lu.\n", *daffodil);
(void) printf("Registering tulip: %lu.\n", *tulip);
(void) printf("Registering carnation: %lu.\n",*carnation);
(void) printf("Registering lily: %lu.\n", *lily);
(void) printf("Registering crocus: %lu.\n", crocus);
(void) printf("Registering zinnia: %lu.\n", *zinnia);
carnation = (unsigned long *) NULL;
free(daffodil);
free(carnation);
return EXIT_SUCCESS;
}这就是我在航站楼做的事:

发布于 2016-02-15 11:10:32
为了查看GDB中的局部变量,您必须中断该函数中的程序执行。您正在尝试打印程序终止后的值,这是不可能的。
尝试在第10行放置一个断点,我认为:
(gdb) br 10
(gdb) run
(gdb) print tulip您还可以在main开始时中断,然后前进,直到初始化变量为止:
(gdb) br main
(gdb) run
(gdb) next
(gdb) next
(gdb) ...
(gdb) print tulipmain的断点非常频繁,以至于gdb有一个自动执行该操作的命令:start。
如果您对变量特别感兴趣,则可以显示它,以便在每一步都自动打印它:
(gdb) start
(gdb) display tulip
(gdb) next
(gdb) next
(gdb) ...https://stackoverflow.com/questions/35407741
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