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社区首页 >问答首页 >TimeAgo函数返回负秒

TimeAgo函数返回负秒
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Stack Overflow用户
提问于 2016-02-12 20:56:15
回答 1查看 97关注 0票数 0

我有一个函数,返回多久前发布的时间,但似乎有一个轻微的问题。第一次,$timeAgo1工作得很好,但是第二次,$timeAgo2似乎返回负秒。这是怎么回事?

代码语言:javascript
复制
<?php

//*****************************************************START OF FUNCTION
function timeAgo($time_ago) {

    $time_ago = strtotime($time_ago);
    $cur_time = time();
    $time_elapsed = $cur_time - $time_ago;
    $seconds = $time_elapsed ;
    $minutes = round($time_elapsed / 60 );
    $hours = round($time_elapsed / 3600);
    $days = round($time_elapsed / 86400 );
    $weeks = round($time_elapsed / 604800);
    $months = round($time_elapsed / 2600640 );
    $years = round($time_elapsed / 31207680 );

    echo $seconds."<br>";
    if ($seconds <= 60) {
        return "just now";
    } //end of if ($seconds <= 60)

    else if ($minutes <=60) {
        if ($minutes == 1) {
            return "one minute ago";
        } //end of else if ($minutes <=60)
        else {
            return "$minutes minutes ago";
        } //end of else not ($minutes == 1)
    } //end of else if ($minutes <= 60)


    else if ($hours <= 24) {
        if ($hours == 1) {
            return "an hour ago";
        } //end of if ($hours == 1)
        else {
            return "$hours hours ago";
        } //end of else not ($hours == 1)
    } //end of else if ($hours <= 24)


    else if ($days <= 7) {
        if ($days == 1) {
            return "yesterday";
        } //end of else if ($days <= 7)
        else {
            return "$days days ago";
        } //end of else not ($days == 1)
    } //end of else if ($days <= 7)

    else if ($weeks <= 4.3) {
        if ($weeks == 1) {
            return "a week ago";
        } //end of if ($weeks == 1)
        else {
            return "$weeks weeks ago";
        } //end of else not ($weeks == 1)
    } //end of else if ($weeks <= 4.3)


    else if ($months <= 12) {
        if ($months == 1) {
            return "a month ago";
        } //end of if ($months == 1)
        else {
            return "$months months ago";
        } //end of else not ($months == 1)
    } //end of else if ($months <= 12)

    else {
        if ($years == 1) {
            return "one year ago";
        } //end of if ($years == 1)
        else {
            return "$years years ago";
        } //end of else not ($years == 1)
    } //end of last else

} //end of function timeAgo($time_ago)
//*****************************************************END OF FUNCTION

$date1 = "2016-02-10";
$time1 = "22:41:58";
$date2 = "2016-02-12";
$time2 = "15:25:57";

$timeAgo1 = timeAgo($date1.$time1);
$timeAgo2 = timeAgo($date2.$time2);

echo $timeAgo1."<br>".$timeAgo2;

?>
EN

回答 1

Stack Overflow用户

发布于 2016-02-12 21:06:58

这可能与您的服务器有关,因为我使用了两个不同的服务器,结果是

代码语言:javascript
复制
166733
20094
2 days ago
6 hours ago

您的服务器可能位于与您所处位置不同的位置,因此time();函数显示的时间戳与您可能预期的不同。

第二个timeAgo的时间戳为1455290705,因此您的服务器可能位于它/曾经超过1455290705的某个地方。

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/35372051

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