用于Coursera分配的无效输出

Question

我正在为每个人做Coursera流，我被困在10.2作业中。我的输出是无效的。以下是任务要求：

编写一个程序来读取Mbox-短路. out，并按一天中每条消息的小时计算出分布。您可以从“from”行中提取时间，方法是找到时间，然后使用冒号再次拆分字符串。 2008年1月5日09:14:16从stephen.marquard@uct.ac.za Sat出发 一旦积累了每小时的计数，就打印出计数，按小时排序，如下所示。

这是我的代码：

name = raw_input("Enter file:")
if len(name) < 1 : name = "mbox-short.txt"
handle = open(name)
counts = dict()
lst = list()

for line in handle:
    line = line.rstrip()
    if not line.startswith('From '):
        continue
    words = line.split()
    words = words[5]
    words = words.split(":")
    for word in counts:
        counts[word] = counts.get(word, 0) + 1

lst = list()
for key, val in counts.items():
    lst.append((key, val))

lst.sort()

print lst

告诉我我做错了什么。如有任何建议或提示，我们将不胜感激。

Answer 1

我认为您正在内部循环中迭代错误的东西:它应该是for word in words，而不是for word in counts。

Answer 2

name = raw_input("Enter file:")
if len(name) < 1 : name = "mbox-short.txt"

handle = open(name)

hours = dict()

for line in handle:
   if line.startswith("From "):

    hour = line.split()[5].split(':')[0] 

    hours[hour] = hours.get(hour, 0) + 1

for key, value in sorted(hours.items(), None):
    print key, value

Answer 3

name = input("Enter file:")
if len(name) < 1 : name = "mbox-short.txt"
handle = open(name)


counts = {}

for line in handle:
   if not line.startswith("From "):continue

   time = line.split()
   time = time[5]
   hour = time.split(':')
   hour = hour[0] 

   counts[hour] = counts.get(hour, 0) + 1


for k, v in sorted(counts.items()):

    print (k,v)