原始sql查询:
SELECT *
FROM
(SELECT p.id,
p.title,
p.mark,
(SELECT max(created)
FROM comments c
WHERE c.post_id=p.id
AND c.mark=1) AS latest_at
FROM posts p) AS Post
WHERE Post.latest_at IS NOT NULL
ORDER BY latest_at DESC LIMIT 10我有两张桌子:
$postsTable = TableRegistry::get('Posts');
$comments = TableRegistry::get('Comments');我已经用cakephp-3方式进行了内部查询:
SELECT p.id,
p.title,
p.mark,
(SELECT max(created)
FROM comments c
WHERE c.post_id=p.id AND c.mark=1) AS latest_at
FROM posts pCakephp-3内部sql与cakephp-3 querybuilder(下面的查询正确吗?):
$subquery = $comments->find();
$subquery->select([$subquery->func()->max('created')])
->from(['c'=>'comments'])
->where(['c.post_id=p.id','mark=1']);
$pquery = $postsTable->find()
->select(['p.id','p.title','p.mark','latest_at'=>$subquery])
->from(['p'=>'posts']);如何用cakephp-3方式编写外部选择查询?(从(派生表)中选择*)
提前谢谢。如有任何答复,将不胜感激。
发布于 2016-02-14 11:39:54
要直接回答您的问题,以下是如何在另一个查询的from部分中使用子查询:
$query = $this->MyTable->connection()->newQuery();
$query->select('*')->from(['Post' => $subqueryObject])->fetchAll('assoc');这将返回结果数组,如果您知道它应该水化到哪种类型的实体,那么执行以下操作:
$query = $this->Posts
->find()
->select($listOfFields)
->from(['Posts' => $subqueryObject], true)
->toArray();发布于 2016-02-14 08:52:42
对于一个非常简单的问题,这是一个非常复杂的解决方案(即用最新的评论获得帖子)。
更好的查询是:
select posts.* from posts join comments on (comments.post_id = posts.id) group by posts.id order by comments.created desc limit 1执行此查询的ORM方法是:
$post = $postsTable
->find()
->select(['Posts.id', 'Posts.title', 'Posts.mark', 'Comments.created'])
->leftJoinWith('Comments', function ($q) {
return $q->where(['Comments.mark' => true]);
}))
->group(['Posts.id'])
->order(['Comments.created' => 'desc'])
->first();发布于 2016-02-13 21:59:55
对于特殊情况,cakephp允许您编写原始SQL并保持cakephp方式。只需在您的模型中创建一个函数,您就可以通过将其放在$this->query("...")中,以其方式编写该查询。
示例(在模型中):
public function getPosts(){
$this->query("SELECT * FROM Posts AS Post"); //put complext query here
}然后在主计长:
$posts = $this->Post->getPosts();https://stackoverflow.com/questions/35358203
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