这个php确实给了我一些问题。我想从数据库中返回数据,我希望它显示来自数据库的主要数据,我希望它显示来自数据库的数据,以匹配从数据库输入的信息--例如,如果我输入名称"Paul Mason“并单击search按钮,它连接到数据库并回显站点上的信息。
下面显示了我编写的代码。
<html>
<title>Search Records</title>
<head>
<body>
<form name="" id="" method="post" action="search.php"/>
<p> Enter Student name : <input type="text" name="fullname" id="fullname"/>
<input type="submit" name="senda" value="Search Data" />
</form>
<?php
if(isset($_POST['senda'])){
include 'mysqlconn.php';
$con = mysqli_connect($host, $dbuser, $pass, $db) or die('Cannot Connect');
$name = $_POST['fullname'];
$sql = "SELECT * FROM scores WHERE MATCH(fullname) AGAINST('$name')";
$result = mysqli_query($con,$sql) or die("Error: ".mysqli_error($con));
while($row = mysqli_fetch_array($result,MYSQLI_ASSOC))
{
printf("%s (%s)\n", $row['Fullname'] ." ". $row['studentNo'] ." ". $row['SubjectName'] ." ". $row['GPA'] ." ". $row['CGPA'] ." ". $row['SCORE']);
mysqli_free_result($result);
}
mysqli_close($con);
}
?>
</body>
</head>
</html>相反,它显示了其他类似的东西:Error: Can't find FULLTEXT index matching the column list
什么是错的,我需要有人来纠正我的编程!
发布于 2016-02-09 13:20:36
在要引用的列上没有全文索引。对于单个列搜索,如果不希望创建索引,请尝试(也转换为为您准备的语句):
对于松散的比赛:
$con = new mysqli($host, $dbuser, $pass, $db) or die('Cannot Connect');
$name = $_POST['fullname'];
$query = $con->prepare("SELECT * FROM scores WHERE fullname LIKE '%$name%'");
$query->execute();准确匹配:
$con = new mysqli($host, $dbuser, $pass, $db) or die('Cannot Connect');
$name = $_POST['fullname'];
$query = $con->prepare("SELECT * FROM scores WHERE fullname = '$name'");
$query->execute();如果您确实有或创建了一个完整的文本索引,那么它将工作,但仍然建议准备查询以防止注入攻击:
$con = new mysqli($host, $dbuser, $pass, $db) or die('Cannot Connect');
$name = $_POST['fullname'];
$query = $con->prepare("WHERE MATCH(fullname) AGAINST('$name')");
$query->execute();https://stackoverflow.com/questions/35292767
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