DocumentFile.fromFile on 5.0+

Question

在我的测试中，我发现使用fromFile创建的任何fromFile都会在5.0+上失败(createFile、createDirectory等)，即使您获得了SAF对根的权限。

这是预期的行为吗？

如果fromFile只是为了实现<5.0的兼容性，我真的希望它们在文档中已经清楚了。

Answer 1

因此，fromFile生成一个RawDocumentFile，它似乎简单地包装了一个文件。我看不出这将如何提供File本身不具有的任何额外的写权限，而不管SAF权限如何，所以我要说的是，fromFile应该仅仅充当一个向后兼容性(<4.4)工厂。我已经提交了一个增强请求来更新文档来解释这一点。

Answer 2

如果不想使用ACTION_OPEN_DOCUMENT_TREE或ACTION_OPEN_DOCUMENT获取Uri，可以使用从API19(Android4.4-Kitkat)到API28(Android8-Oreo)的有效方法将文件转换为Uri (SAF)：

 /**
 * Ing.N.Nyerges 2019 V2.0
 *
 * Storage Access Framework(SAF) Uri's creator from File (java.IO),
 * for removable external storages
 *
 * @param context Application Context
 * @param file File path + file name
 * @return Uri[]:
 *   uri[0] = SAF TREE Uri
 *   uri[1] = SAF DOCUMENT Uri
 */
@RequiresApi(api = Build.VERSION_CODES.KITKAT)
public static Uri[] getSafUris (Context context, File file) {

    Uri[] uri = new Uri[2];
    String scheme = "content";
    String authority = "com.android.externalstorage.documents";

    // Separate each element of the File path
    // File format: "/storage/XXXX-XXXX/sub-folder1/sub-folder2..../filename"
    // (XXXX-XXXX is external removable number
    String[] ele = file.getPath().split(File.separator);
    //  ele[0] = not used (empty)
    //  ele[1] = not used (storage name)
    //  ele[2] = storage number
    //  ele[3 to (n-1)] = folders
    //  ele[n] = file name

    // Construct folders strings using SAF format
    StringBuilder folders = new StringBuilder();
    if (ele.length > 4) {
        folders.append(ele[3]);
        for (int i = 4; i < ele.length - 1; ++i) folders.append("%2F").append(ele[i]);
    }

    String common = ele[2] + "%3A" + folders.toString();

    // Construct TREE Uri
    Uri.Builder builder = new Uri.Builder();
    builder.scheme(scheme);
    builder.authority(authority);
    builder.encodedPath("/tree/" + common);
    uri[0] = builder.build();

    // Construct DOCUMENT Uri
    builder = new Uri.Builder();
    builder.scheme(scheme);
    builder.authority(authority);
    if (ele.length > 4) common = common + "%2F";
    builder.encodedPath("/document/" + common + file.getName());
    uri[1] = builder.build();

    return uri;
}