我试着用文士和行,我总是得到以下的答案:
Can't extract token and secret from this: '{"message":"Invalid OAuth signature","error_name":"INVALID_OAUTH_SIGNATURE"}'我有一个有效的登录过程,返回一个oauth_token和一个oauth_verifier,并试图用PlainText签名更改默认选择的HMACSha1签名,但我将始终得到上述结果.
对为什么会发生这种事有什么想法吗?
在上面提到的步骤中使用默认的DefaultApi10a和XingApi总是失败的。
编辑-代码
// Creating the service
// callback is needed to stop redirecting in the webview
OAuthService service = new ServiceBuilder()
.provider(XingApi.class)
.apiKey(apiKey)
.apiSecret(apiSecret)
.callback("http://www.xing.com")
.build();步骤1:获取请求令牌+ auth url
RequestToken requestToken = service.getRequestToken();
String authUrl = service.getAuthorizationUrl(requestToken );步骤2:在webview中加载auth url +检查重定向url并根据回调取消重定向
例如,重定向url如下所示:http://www.xing.com?oauth_token=a2191ab84c9e0f85cf0c&oauth_verifier=4978
步骤3:从返回的url中提取oauth_token + oauth_verifier
String oauthToken = ...; // a2191ab84c9e0f85cf0c in the example
String oauthVerifier = ...; // 4978 in the example步骤4:获取访问令牌=>失败
Token requestToken = new Token(oauthToken, oauthVerifier); // reusing the request token from above results in invalid request token answer from xing!
Verifier v = new Verifier(oauthVerifier);
Token accessToken = service.getAccessToken(requestToken, v);发布于 2016-02-01 20:39:20
移除:
Token requestToken = new Token(oauthToken, oauthVerifier); // reusing the request token from above results in invalid request token answer from xing!
从第四步开始。
您必须保存请求令牌才能使用请求令牌和验证器(4位PIN)从Xing检索访问令牌。
编辑-代码添加:
OAuth10aService service = new ServiceBuilder()
.apiKey("44a4f9c1a9daa88f4da2")
.apiSecret("2fc8ca373dab772acc4de7ce22718f8fced6919c")
.callback("https://redirect.example.com")
.build(XingApi.instance());
final Token requestToken = service.getRequestToken();
System.out.println(service.getAuthorizationUrl(requestToken));
System.out.println("Paste the verifier here");
System.out.print(">>");
Scanner in = new Scanner(System.in);
Verifier verifier = new Verifier(in.nextLine());
System.out.println();
in.close();
// Trade the Request Token and Verfier for the Access Token
Token accessToken = service.getAccessToken(requestToken, verifier);
System.out.println("Got the Access Token! " + accessToken);https://stackoverflow.com/questions/35114626
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