使用magrittr

Question

我想用magrittr的管道重写以下代码：

max(diff(which(diff(runif(50)) > 0 )))

我直截了当的做法是：

library(magrittr)
runif(50) %>% diff > 0 %>% which %>% diff %>% max

但是由于(第一个)

runif(50) %>% diff > 0 %>% which

错误，其中(.)：参数指向“哪个”不符合逻辑

我不知道为什么会发生此错误，以及为什么管道与管道与其他函数不同，因为"diff > 0“的输出是一个逻辑向量。

直截了当地说，在一个侧面，会有什么方法来进行比较吗？

 runif(50) %>% diff %>% > 0 

Answer 1

尝试：

runif(50) %>% diff %>% `>`(0) %>% which %>% diff %>% max

编辑:应该指出，这些是后排，而不是引号。

Answer 2

我相信您的问题字符串被解析为等价于：

(runif(50) %>% diff) > (0 %>% which %>% diff %>% max)

它返回相同的错误。

另一方面，除了已经提出的建议外，这些建议也很好：

runif(50) %>% {diff(.) > 0} %>% which %>% diff %>% max
(runif(50) %>% diff > 0) %>% which %>% diff %>% max