Lua "if to“语句出错(”end“预期(在第28行结束'if‘))

Question

我有个错误说

bios:14:字符串“照明”：58:预期结束(在第28行结束'if‘)

老实说，我不知道自己在做什么，因为我对Lua和一般的编码都很陌生。我认为这与在某个地方没有end有关。

term.clear()
term.setCursorPos(17, 4)
print("Welcome")
sleep(2)
term.setCursorPos(8, 5)
print("What lights would you like to control?")
input = read()
if input == "Hall" then
  term.clear()
  term.setCursorPos(17,4)
  print("On or Off?")
  input = read()
  if input == "on" then
    redstone.setOutput("back", true)
    print("Hall Lighting Turned On")
    sleep(5)
    shell.run("Lighting")
  else
    redstone.setOutput("back", false)
    print("Hall Lighing Turned Off")
    sleep(5)
    shell.run("Lighting")
  if input == "Bedroom" then
  term.clear()
  term.setCursorPos(17,4)
  print("On or Off")
  input = read()
  if input == "on" then
    redstone.setOutput("left", true)
    print("Bedroom Lighting Turned On")
    sleep(5)
    shell.run("Lighting")
  else
    redstone.setOutput("left", false)
    print("Bedroom Lighing Turned Off")
    sleep(5)
    shell.run("Lighting")
  if input == "Labs" then
  term.clear()
  term.setCursorPos(17,4)
  print("On or Off?")
  input = read()
  if input == "on" then
    redstone.setOutput("right", true)
    print("Lab Lighting Turned On")
    sleep(5)
    shell.run("Lighting")
  else
    redstone.setOutput("right", false)
    print("Lab Lighing Turned Off")
    sleep(5)
    shell.run("Lighting")
  end
else
  print("Error")
  sleep(3)
  shell.run("Lighting")
end

Answer 1

看起来您在几个地方缺少了end单词。

其结构应如下：

if ... then
  some code
else
  some optional code
end

此外，尝试更好地缩进您的代码。这样你就会清楚地知道你应该把end单词放在哪里。

你想要的可能是：

term.clear()
...
input = read()

if input == "Hall" then
  ...
  if input == "on" then
    ...
  else
    redstone.setOutput("back", false)

    shell.run("Lighting")
  end -- missing end!
end -- missing end!

if input == "Bedroom" then
    ...
  if input == "on" then
    ...
  else
    redstone.setOutput("left", false)
    ...
    shell.run("Lighting")
  end -- missing end!
end -- missing end!

...