如何使用dulwich签出特定的文件或目录

Question

我有一个基于dulwich的工作结账功能：

def checkout(repo, ref=None):
    if ref is None:
        ref = repo.head()
    index = repo.index_path()
    tree_id = repo[ref].tree
    build_index_from_tree(repo.path, index, repo.object_store, tree_id)
    return [repo.object_store.iter_tree_contents(tree_id)]

但是我如何修改它以签出一个单独的文件或目录呢？

有什么东西可以取代build_index_from_tree线吗？

Answer 1

内联build_index_from_tree()的内容，然后添加一个if语句，以筛选出没有以路径开头的entry.path的任何条目：

if subpath[-1] != "/":
    subpath += "/"

if not isinstance(root_path, bytes):
    root_path = root_path.encode(sys.getfilesystemencoding())

for entry in object_store.iter_tree_contents(tree_id):
    if not validate_path(entry.path, validate_path_element_default):
        continue
    # new lines added here:
    if not entry.path.startswith(subpath):
        continue
    full_path = _tree_to_fs_path(root_path, entry.path[len(subpath):])

    if not os.path.exists(os.path.dirname(full_path)):
        os.makedirs(os.path.dirname(full_path))

    obj = object_store[entry.sha]
    build_file_from_blob(obj, entry.mode, full_path)

Answer 2

看起来杰尔默之前可能回答过这个问题：http://www.aaronheld.com/post/using-python-dulwich-to-load-any-version-of-a-file-from-a-local-git-repo