如何在类中包含来自另一个方法的print语句

Question

我的问题是如何更改我的代码，以便它打印出我的第一行打印和从testBuildCodonMap方法打印的行？目前没有打印出来的打印行是System.out.println(s+"\t"+codonMap.get(s));。我想把这个和其他打印声明一起包括进去。

import java.util.*;
import edu.duke.*;

public class CodonCount {
    private HashMap<String,Integer> codonMap;
    public CodonCount() {
        codonMap = new HashMap<String,Integer>();
    }
    private void buildCodonMap(int start, String dna) {
        //clear out map before building
        codonMap.clear();
        //This method will build a new map of codons mapped to 
        //their counts from the string dna with the reading frame
        //with the position start (a value of 0, 1, or 2).
        for (int index=start; dna.length() - index > 3;index+=3) {
            String currentCodon = dna.substring(index,index+3);
            if (!codonMap.containsKey(currentCodon)) {
                codonMap.put(currentCodon,1);
            }
            else {
                codonMap.put(currentCodon,codonMap.get(currentCodon)+1);
            }
        }
    }
    private String getMostCommonCodon() {
        //get the codon in a reading frame that has the largest count
        //this method assumes the HashMap of codons to counts has already been built
        int currentHigh = 0;
        String mostCommonCodon = "";
        for (String s : codonMap.keySet()) {
            int currentCount = codonMap.get(s);
            if (currentCount > currentHigh) {
                mostCommonCodon = s;
                currentHigh = currentCount;
            }
        }
        return mostCommonCodon;
    }
    private void printCodonCounts(int start, int end) {
        //This method prints all the codons in the HashMap along with their
        //counts if their count is between start and end, inclusive.
        for (String s : codonMap.keySet()) {
            if (codonMap.get(s) >= start && codonMap.get(s) <= end) {
                System.out.println(s+"\t"+codonMap.get(s));
            }
        }
    }
    public void testBuildCodonMap() {
        FileResource fileResource = new FileResource();
        String dna = fileResource.asString();
        dna = dna.toUpperCase();

        for (int index=0;index <= 2;index++) {
            System.out.println("\nTesting with start position "+index+":\n");
            buildCodonMap(index,dna);
            String mostCommonCodon = getMostCommonCodon();
            System.out.println("Total unique codons found: "+codonMap.size());
            System.out.println("\nMost common codon: "+mostCommonCodon
                                +"\t"+codonMap.get(mostCommonCodon));
            printCodonCounts(4,8);
        }
    }
}

用于测试的示例文件： CGTTCAAGTTCAA

编辑：--我希望输出如下所示：

从0开始的阅读框产生了3个唯一的密码子

最常见的密码子是具有计数2的TCA。

包括在1至5之间的密码子数如下：

CGT 1

TCA 2

AGT 1

从1开始的阅读框会产生两个独特的密码子

最常见的密码子是具有计数2的CAA。

包括在1至5之间的密码子数如下：

CAA 2

GTT 2

从2开始的阅读框架导致了两个独特的密码子

最常见的密码子是具有计数2的TTC。

包括在1至5之间的密码子数如下：

TTC 2

AAG 1

Answer 1

这样啊，原来是这么回事!需要将public void testBuildCodonMap()方法中的行public void testBuildCodonMap()更改为printCodonCounts(1,3);。它允许方法private void printCodonCounts(int start, int end)中的print语句执行。