如何在MVC配置中允许匿名twitter连接

Question

使用- spring-social 1.1.4 - spring-social-twitter 1.1.2 -spring 4.2- on tomcat 7

下面是我的MVC应用程序的tomcat配置，包括twitter和usersConnectionRepository。

对于登录到MVC的用户来说，这一切都很好。

当我希望允许客户端从非MVC认证用户可用的公共链接上发布消息时，我就会遇到这个问题。(#{request.userPrincipal.name}将为空)

我看过很多例子。大多数示例使用旧的1.0.0 spring-social。我注意到新的1.1.2版本的spring-social-twitter没有零参数Twitter()构造函数，在一些例子中，这是一种不用connectionRepository就能工作的方法。

我正在寻找一种方法来配置或编码一个选项，允许登录到我的应用程序的用户和匿名用户在我的站点上使用一些选项。

在下面的配置中，匿名用户被重定向到连接/twitter将导致获取connetionRepository的问题。usersConnectionRepository必须具有"#{request.userPrincipal.name}“，因为我的connectController依赖于此。

我在想也许我需要一个定制的连接控制器..。必须对此采取正确的办法。

欢迎任何建议。

我的web.xml

    <listener>
  <listener-class>
          org.springframework.web.util.Log4jConfigListener
      </listener-class>
</listener>


<display-name>Central Portal</display-name>

<context-param>  
    <param-name>spring.profiles.active</param-name>  
    <param-value>dev</param-value>  
</context-param>  
<context-param>  
    <param-name>spring.profiles.default</param-name>  
    <param-value>dev</param-value>  
</context-param>
<context-param>  
    <param-name>spring.liveBeansView.mbeanDomain</param-name>  
    <param-value>dev</param-value>  
</context-param> 

<!-- Spring MVC -->
<servlet> 
    <servlet-name>mvc-dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>mvc-dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

<error-page>
    <error-code>500</error-code>
    <location>/WEB-INF//pages/error.jsp</location>
</error-page>

<error-page>
    <error-code>404</error-code>
    <location>/WEB-INF/pages/error.jsp</location>
</error-page>

<error-page>
    <location>/WEB-INF/pages/error.jsp</location>
</error-page>
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>
        /WEB-INF/spring-security.xml,
        /WEB-INF/spring-database.xml   
    </param-value>
</context-param> 



<!-- Enable POST  --> 
<filter>
    <filter-name>hiddenHttpMethodFilter</filter-name>
    <filter-class>org.springframework.web.filter.HiddenHttpMethodFilter</filter-class>
</filter>

<filter-mapping>
    <filter-name>hiddenHttpMethodFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>


<!-- Spring Security -->
<filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>

<filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

<!-- Concurrency listener -->
<listener>
    <listener-class>
        org.springframework.security.web.session.HttpSessionEventPublisher
    </listener-class>
</listener>

一点java配置

​

mvc-dispatcher-servlet.xml

<context:component-scan base-package="org.schoolit.usermanager.config" /> 

<!-- component-scan / controllers -->
<context:component-scan base-package="org.schoolit.webapplication.*" />
<context:component-scan base-package="org.schoolit.spring.social.*"/>

<!-- property-placeholder's  -->
<context:property-placeholder location="classpath:oauth.properties"/>

<!-- resource mapping  -->
<mvc:resources mapping="/gen/**" location="/WEB-INF/gen/" cache-period="31556926"/>
<mvc:resources mapping="/resources/**" location="/WEB-INF/resources/" cache-period="31556926"/>

<!-- JSP ViewResolver -->
<bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="prefix">
        <value>/pages/</value>
    </property>
    <property name="suffix">
        <value>.jsp</value>
    </property>
</bean>

<!-- twitter stuff start --> 
<bean id="handlerExceptionResolver" class="org.springframework.web.servlet.handler.SimpleMappingExceptionResolver">
    <property name="exceptionMappings">
        <props>
            <prop key="Exception">error</prop>
        </props>
    </property>
</bean> 

 <bean id="twitterTemplate" 
    class="org.springframework.social.twitter.api.impl.TwitterTemplate">
    <constructor-arg value="${twitter.oauth.consumerKey}"/>
    <constructor-arg value="${twitter.oauth.consumerSecret}"/>
<!--<constructor-arg value="${twitter.oauth.accessToken}"/>
    <constructor-arg value="${twitter.oauth.accessTokenSecret}"/>   --> 
</bean> 



<bean id="connectionFactoryLocator" class="org.springframework.social.connect.support.ConnectionFactoryRegistry">
    <property name="connectionFactories">
        <list>
            <bean class="org.springframework.social.twitter.connect.TwitterConnectionFactory">
                <constructor-arg value="${twitter.oauth.consumerKey}" />
                <constructor-arg value="${twitter.oauth.consumerSecret}" />          
            </bean>
        </list>
    </property>
</bean>  


<bean id="connectionRepository" factory-method="createConnectionRepository" factory-bean="usersConnectionRepository" scope="request">
    <constructor-arg value="#{request.userPrincipal.name}" />
    <aop:scoped-proxy proxy-target-class="true" />
</bean>

<bean id="usersConnectionRepository" 
      class="org.springframework.social.connect.jdbc.JdbcUsersConnectionRepository">
    <constructor-arg ref="dataSource" />
    <constructor-arg ref="connectionFactoryLocator" />
    <constructor-arg ref="textEncryptor" />
</bean>

<bean id="textEncryptor" class="org.springframework.security.crypto.encrypt.Encryptors" 
            factory-method="noOpText" />

 <bean id="connectController" class="org.springframework.social.connect.web.ConnectController">
    <constructor-arg ref="connectionFactoryLocator"/>
    <constructor-arg ref="connectionRepository"/>
    <property name="applicationUrl" value="http://localhost:8080/CentralPortal/" />
    <property name="connectInterceptors">
            <list> 
                <bean class="org.schoolit.spring.social.TweetAfterConnectInterceptor"/>
            </list>
    </property> 
</bean>       

spring-database.xml

    <!-- App's dataSource used by jdbcTemplate,jdbc-user-service and connectController -->
<bean id="dataSource"
    class="org.springframework.jdbc.datasource.DriverManagerDataSource">
    <property name="driverClassName" value="com.mysql.jdbc.Driver" />
    <property name="url" value="jdbc:mysql://localhost:3306/spring_me" />
    <property name="username" value="root" />
    <property name="password" value="<mypassword>" />
</bean>

<!-- jdbcTemplate used in usermanager bit only for now. --> 
<bean id="jdbcTemplate" class="org.springframework.jdbc.core.namedparam.NamedParameterJdbcTemplate">
    <constructor-arg ref="dataSource" /> 
</bean>

spring-security.xml

  <!-- enable use-expressions -->
<http auto-config="true" use-expressions="true"> 

    <!-- Set up rolefilter's for requestmapping's -->
    <intercept-url pattern="/admin**" access="hasRole('ROLE_ADMIN')" />
    <intercept-url pattern="/usermanager**" access="hasRole('ROLE_ADMIN')" />  
    <intercept-url pattern="/users**" access="hasRole('ROLE_ADMIN')" />


    <!-- access denied page --> 
    <access-denied-handler error-page="/403" /> 
    <!-- loginform-setup Spring Security -->
    <form-login 
        login-page="/login" 
        default-target-url="/home" 
        login-processing-url="/j_spring_security_check"
        authentication-failure-url="/login?error" 
        username-parameter="username"
        password-parameter="password" /> 
    <logout logout-success-url="/login?logout"  />

    <!-- enable csrf protection default is enabled from 4.0 spring 
    <csrf /> <csrf disabled="true"/>  -->
     <csrf request-matcher-ref="connect/*" disabled="true"/>

    <!-- Prevent Clickjacking iframe's  --> 
    <headers>
        <frame-options policy="SAMEORIGIN"/> 
    </headers>  
    <!-- One login per username should be one set to 5 for testing-->
    <session-management>
        <concurrency-control max-sessions="1" error-if-maximum-exceeded="true" expired-url="/login?error"   /> 
    </session-management>
</http>

<!-- Select users and user_roles from database -->
<authentication-manager>
    <authentication-provider>
    <password-encoder ref="encoder" />
        <jdbc-user-service data-source-ref="dataSource"
            users-by-username-query="select username,password, enabled from users where username=?"
            authorities-by-username-query="select username, role from user_roles where username =?  " />
    </authentication-provider>
</authentication-manager>

<!-- encoder bean. Used for password encryption -->
<beans:bean id="encoder" 
    class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder">
    <beans:constructor-arg name="strength" value="11" />
</beans:bean>

Answer 1

我看到您已经配置了twitterTemplate bean，如果您能够在应用程序中使用它，您就不需要做任何其他事情了。

使用TwitterTemplate而不是Twitter。TwitterTemplate实现了Twitter接口，因此所有方法都是可用的。

示例：

//1. Search Twitter
SearchResults results = twitterTemplate.searchOperations().search("#WinterIsComing");
List<Tweet> tweets = results.getTweets();
int i =0;
for (Tweet tweet : tweets) {
    System.out.println(tweet.getUser().getName() + " Tweeted : "+tweet.getText() + " from " + tweet.getUser().getLocation() 
            + " @ " + tweet.getCreatedAt() + tweet.getUser().getLocation()  );
}

//2. Search Place by GeoLocation        
RestTemplate restTemplate = twitterTemplate.getRestTemplate();
GeoTemplate geoTemplate = new GeoTemplate(restTemplate, true, true);
List<Place> place = geoTemplate.search(37.423021, -122.083739);
for (Place p : place) {
    System.out.println(p.getName() + " " + p.getCountry() + " "+p.getId());
}           

//3. Get Twitter UserProfile
TwitterProfile userProfile = twitterTemplate.userOperations().getUserProfile();
System.out.println(userProfile.getName()+" has " +userProfile.getFriendsCount() + " friends");

使用TwitterTemplate，用户不需要登录。希望这能有所帮助！