Python:无法打印要文件的5个列表的元组

Question

我试图在Python中将5个列表的元组打印到一个文件中，但是，我得到了错误：

TypeError: Can't convert 'tuple' object to str implicitly

以下是我的代码：

def listjoin():
illegallist = zip(carreglist, illegalspeed, illegaltime, illegalname, illegaladdress)
for item in illegallist:
    illegaldatafile.write("Registration: "+item)
    illegaldatafile.write("\n")
    illegaldatafile.write("Speed "+item)
    illegaldatafile.write("\n")
    illegaldatafile.write("Time: "+item)
    illegaldatafile.write("\n")
    illegaldatafile.write("Name: "+item)
    illegaldatafile.write("\n")
    illegaldatafile.write("Address: "+item)
    illegaldatafile.write("\n")
    illegaldatafile.write("\n")
    illegaldatafile.close()

我想得到这样的东西：

Registration: BH34JKX
Speed: 80
Time: 6:45:21
Name: John Adams
Address: SW34 7MN

Registration: DX34JKS

等等。(不小心发布得太早)

我在前面的代码中将一个列表打印到一个文件中，它不需要转换为字符串。我不能这么做：

illegallist = zip(str(carreglist, illegalspeed, illegaltime, illegalname, illegaladdress))

因为str()只接受3个参数。我试过把它放在这里：

illegallist = str(zip(carreglist, illegalspeed, illegaltime, illegalname, illegaladdress))

但它只是说我的文件被关闭了。

Answer 1

与其简单地调用每个循环迭代的项( item )，不如将其解压缩，以便更容易地引用每个对象。字符串格式设置也会有帮助：

def listjoin():
    illegallist = zip(carreglist, illegalspeed, illegaltime, illegalname, illegaladdress)
    for reg,speed,timing,name,address in illegallist:
        illegaldatafile.write("Registration: {}\n".format(reg))
        illegaldatafile.write("Speed: {}\n".format(speed))
        illegaldatafile.write("Time: {}\n".format(timing))
        illegaldatafile.write("Name: {}\n".format(name))
        illegaldatafile.write("Address: {}\n\n".format(address))
    illegaldatafile.close()

Answer 2

您正在将相同的元组item一遍又一遍地附加到字符串中。您必须从这个元组中提取单独的元素。这是我(更紧凑)的建议：

colnames = ['Registration', 'Speed', 'Time', 'Name', 'Address']
for tup in zip(carreglist, illegalspeed, illegaltime, illegalname, illegaladdress):
    for colname, value in zip(colnames, tup):
        illegaldatafile.write('{}: {}\n'.format(colname, value))
    illegaldatafile.write('\n')

Answer 3

可以在print参数中使用file语句，如果只有5个元组，则可以使用%

def listjoin():
    illegallist = zip(carreglist, illegalspeed, illegaltime, illegalname, illegaladdress)
    for item in illegallist:
        print("Registration: %s" % item[0], file=illegaldatafile)
        print("Speed: %s" % item[1], file=illegaldatafile)
        print("Time: %s" % item[2], file=illegaldatafile)
        print("Name: %s" % item[3], file=illegaldatafile)
        print("Address: %s" % item[4], file=illegaldatafile)
        print(file=illegaldatafile)
    illegaldatafile.close()