从下表中可以获得每项运动的总价值,例如,使用Javascript/jquery/jquery-plugins:
足球:2板球:1网球:2
<!DOCTYPE html>
<html>
<body>
<table style="width:100%">
<thead>
<tr>
<td>first name</td>
<td>last name</td>
<td>sport</td>
</tr>
</thead>
<tr>
<td>Bob</td>
<td>Smith</td>
<td>football</td>
</tr>
<tr>
<td>Dan</td>
<td>Jackson</td>
<td>cricket</td>
</tr>
<tr>
<td>Will</td>
<td>Rie</td>
<td>Tennis</td>
</tr>
<tr>
<td>Tom</td>
<td>Lawrence</td>
<td>Tennis</td>
</tr>
<tr>
<td>John</td>
<td>croft</td>
<td>football</td>
</tr>
</table>
</body>
</html>我尝试过使用jQuery.size()和.count(),但没有成功。任何建议都会有帮助的!
发布于 2016-01-07 23:35:11
我的建议是:
$(function() {
var result = {};
$('table tr:not(:first)').find('td:last').each(function(index, element) {
var txt = element.innerHTML;
if (!result.hasOwnProperty(txt)) {
result[txt] = 1;
} else {
result[txt]++;
}
});
var resultStr = JSON.stringify(result).replace(/[{}"]/g, '').replace(/,/g, ' ');
alert(resultStr);
});<script src="http://code.jquery.com/jquery-1.11.3.js"></script>
<table style="width:100%">
<thead>
<tr>
<td>first name</td>
<td>last name</td>
<td>sport</td>
</tr>
</thead>
<tr>
<td>Bob</td>
<td>Smith</td>
<td>football</td>
</tr>
<tr>
<td>Dan</td>
<td>Jackson</td>
<td>cricket</td>
</tr>
<tr>
<td>Will</td>
<td>Rie</td>
<td>Tennis</td>
</tr>
<tr>
<td>Tom</td>
<td>Lawrence</td>
<td>Tennis</td>
</tr>
<tr>
<td>John</td>
<td>croft</td>
<td>football</td>
</tr>
</table>
发布于 2016-01-07 22:57:37
创建一个对象,解析表以获取所有最后的td,获取它们的值并将其设置为对象的键,并在它们再次出现时增加它的值。
var sports = {};
$(function() {
$("table tr:not(:first)").each(function(i) {
var sport = $(this).find("td").last().text();
if (sports.hasOwnProperty(sport))
sports[sport] += 1;
else
sports[sport] = 1;
});
console.log(sports);
console.log("Football count is: " + sports.football);
});<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table style="width:100%">
<thead>
<tr>
<td>first name</td>
<td>last name</td>
<td>sport</td>
</tr>
</thead>
<tr>
<td>Bob</td>
<td>Smith</td>
<td>football</td>
</tr>
<tr>
<td>Dan</td>
<td>Jackson</td>
<td>cricket</td>
</tr>
<tr>
<td>Will</td>
<td>Rie</td>
<td>Tennis</td>
</tr>
<tr>
<td>Tom</td>
<td>Lawrence</td>
<td>Tennis</td>
</tr>
<tr>
<td>John</td>
<td>croft</td>
<td>football</td>
</tr>
</table>
发布于 2016-01-07 22:59:25
这将遍历行(忽略第一个行),查看每个行的最后一个td,并将计数添加到counts对象中。如果这项运动以前没有被看到过,它包括一个计数的1,否则,它只是增加已经存在的一个。
编辑:添加jsfiddle:https://jsfiddle.net/1prura93/
$(document).ready(function() {
var rows = $('tr');
var counts = {};
var sport = null;
for (var i = 1; i < rows.length; i++) {
sport = $('td', rows[i]).last().text();
if (!counts[sport]) {
counts[sport] = 1;
} else {
counts[sport]++;
}
}
console.log(counts);
});https://stackoverflow.com/questions/34666656
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