我正在使用视觉API进行人脸检测,现在我想实现眨眼,但在一只眼睛闭上时,视觉api仍然检测眼睛。
请帮助我如何实现眨眼功能。
发布于 2016-01-05 16:13:46
脸部的“睁开概率”值是检测眨眼的关键。此外,您还可以使用跟踪器跟踪眼睛状态随时间的变化,以检测表示眨眼的事件序列:
双眼睁开->双眼闭眼->双眼睁开
下面是一个跟踪器示例:
public class BlinkTracker extends Tracker<Face> {
private final float OPEN_THRESHOLD = 0.85;
private final float CLOSE_THRESHOLD = 0.15;
private int state = 0;
public void onUpdate(Detector.Detections<Face> detections, Face face) {
float left = face.getIsLeftEyeOpenProbability();
float right = face.getIsRightEyeOpenProbability();
if ((left == Face.UNCOMPUTED_PROBABILITY) ||
(right == Face.UNCOMPUTED_PROBABILITY)) {
// At least one of the eyes was not detected.
return;
}
switch (state) {
case 0:
if ((left > OPEN_THRESHOLD) && (right > OPEN_THRESHOLD)) {
// Both eyes are initially open
state = 1;
}
break;
case 1:
if ((left < CLOSE_THRESHOLD) && (right < CLOSE_THRESHOLD)) {
// Both eyes become closed
state = 2;
}
break;
case 2:
if ((left > OPEN_THRESHOLD) && (right > OPEN_THRESHOLD)) {
// Both eyes are open again
Log.i("BlinkTracker", "blink occurred!");
state = 0;
}
break;
}
}
}请注意,您还需要启用“分类”,以便让检测器指示眼睛是否打开/闭着:
FaceDetector detector = new FaceDetector.Builder(context)
.setClassificationType(FaceDetector.ALL_CLASSIFICATIONS)
.build();然后,将跟踪器添加为处理器,用于从检测器接收面部更新。例如,此配置将用于跟踪视图中最大的面是否眨眼:
detector.setProcessor(
new LargestFaceFocusingProcessor(detector, new BlinkTracker()));或者,如果您对检测所有面孔(而不仅仅是最大的脸)的闪烁感兴趣,则可以使用MultiProcessor而不是LargestFaceFocusingProcessor。
发布于 2016-01-04 07:41:49
这个答案假设您已经有了检测面部运行的代码。
Face类具有函数float getIsLeftEyeOpenProbability()和float getIsRightEyeOpenProbability(),如果其中一个函数返回一个较大的值,而另一个函数返回一个较小的值,则可以在每个帧上使用它们来确定其中一个眼睛是否眨眼。
Face类的正式文档可以找到这里
发布于 2018-01-23 00:58:17
这里是我使用FaceDetectorAPi()实现眼睛探测器的应用程序,其测试精度超过90%。
private double leftEyeOpenProbability = -1.0;
private double rightEyeOpenProbability = -1.0;
private boolean isEyeBlinked(){
if(mFaces.size()==0)
return false;
Face face = mFaces.valueAt(0);
float currentLeftEyeOpenProbability = face.getIsLeftEyeOpenProbability();
float currentRightEyeOpenProbability = face.getIsRightEyeOpenProbability();
if(currentLeftEyeOpenProbability== -1.0 || currentRightEyeOpenProbability == -1.0){
return false;
}
if(leftEyeOpenProbability>0.9 || rightEyeOpenProbability > 0.9){
boolean blinked = false;
if(currentLeftEyeOpenProbability<0.6 || rightEyeOpenProbability< 0.6){
blinked = true;
}
leftEyeOpenProbability = currentLeftEyeOpenProbability;
rightEyeOpenProbability = currentRightEyeOpenProbability;
return blinked;
}else{
leftEyeOpenProbability = currentLeftEyeOpenProbability;
rightEyeOpenProbability = currentRightEyeOpenProbability;
return false;
}
}https://stackoverflow.com/questions/34586490
复制相似问题