使用Regex匹配文本行

Question

我有这样的台词：

36600.10: [Host #255] utilization is 0.00%
36600.10: [Host #256] utilization is 21.64%
36600.10: [Host #257] utilization is 3.29%
36600.10: [Host #258] utilization is 0.94%
36600.10: [Host #260] utilization is 3.76%
36600.10: [Host #260] utilization is 1.21%
36600.10: [Host #260] utilization is 86.09%
36600.10: [Host #260] utilization is 7.32%

我需要在utilization is之后得到所有的数字。我想要的是这样一个数组：

myArray[0] => 0.00,
myArray[1] => 21.64,
myArray[2] => 3.29,
myArray[3] => 0.94,
myArray[4] => 3.76,
myArray[5] => 1.21,
myArray[6] => 7.32

到目前为止，我尝试过的(它只适用于第一行)：

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class main {

    public static void main(String[] args) {
          String lines = "36600.10: [Host #256] utilization is 21.65% \n 36600.10: [Host #256] utilization is 91.78% \n 36600.10: [Host #256] utilization is 3.29%";
          String pattern = "(utilization is\\s)(\\d+\\.\\d*)(.*)";

          Pattern r = Pattern.compile(pattern);

          Matcher m = r.matcher(lines);
          if (m.find( )) {
             System.out.println(m.group(2));
          } else {
             System.out.println("NO MATCH");
          }

    }

}

对不起，我是java新手，尝试了一些模式，但没有帮助。任何帮助都将不胜感激。

Answer 1

使用While循环。If语句将限制第一次发生的匹配(正在发生)

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class main {

    public static void main(String[] args) {
          String lines = "36600.10: [Host #256] utilization is 21.65% \n 36600.10: [Host #256] utilization is 91.78% \n 36600.10: [Host #256] utilization is 3.29%";
          String pattern = "(utilization is\\s)(\\d+\\.\\d*)(.*)";

          Pattern r = Pattern.compile(pattern);

          Matcher m = r.matcher(lines);
         while (m.find()) {
             System.out.println(m.group(2));
          } 
    }

}

Answer 2

如果您想使用拆分函数，也可以这样做-

String lines = "36600.10: [Host #256] utilization is 21.65% \n 36600.10: [Host #256] utilization is 91.78% \n 36600.10: [Host #256] utilization is 3.29%";
        String lineArray[] = lines.split("\n");
        for(String temp:lineArray){
            String percentWithSign = temp.split("utilization is")[1];
            String percentStr  = percentWithSign.replace("%", "");
            Float percentFloat = Float.parseFloat(percentStr);
            System.out.println(percentFloat);
        }

Answer 3

它可以在没有正则表达式的情况下得到解决，至少在这种情况下，在看到输入的模式之后。

List<String> list = new ArrayList<String>();
        list.add("36600.10: [Host #255] utilization is 0.00%");
        list.add("36600.10: [Host #256] utilization is 21.64%");
        list.add("36600.10: [Host #255] utilization is 3.29%");
        for(int i=0 ; i<list.size() ; i++){
            String str = list.get(i);
            int start = str.lastIndexOf(" ");
            String temp = str.substring(start+1, str.length()-1);
            System.out.println(temp);
        }