我想要做的是保存一个用户,然后保存一个餐厅实体。我以为这会很容易,但似乎我没能理解什么。
userService.save(user); //this one runs just fine
selectedRestaurant.getEmployees().add(user);
restaurantService.save(selectedRestaurant); //exception两者之间的关系是@OneToMany。不使用事务注释。我认为第一个交易也会打开并关闭,而第二个交易也会这样做。但在试图拯救餐厅之后我明白了:
[[ACTIVE] ExecuteThread: '5' for queue: 'weblogic.kernel.Default (self-tuning)'] DEBUG org.hibernate.engine.jdbc.internal.LogicalConnectionImpl - Obtaining JDBC connection
[[ACTIVE] ExecuteThread: '5' for queue: 'weblogic.kernel.Default (self-tuning)'] DEBUG org.hibernate.engine.jdbc.internal.LogicalConnectionImpl - Obtained JDBC connection
[[ACTIVE] ExecuteThread: '5' for queue: 'weblogic.kernel.Default (self-tuning)'] DEBUG org.hibernate.engine.jdbc.internal.JdbcCoordinatorImpl - Skipping aggressive release due to registered resources
[[ACTIVE] ExecuteThread: '5' for queue: 'weblogic.kernel.Default (self-tuning)'] DEBUG org.hibernate.jpa.spi.AbstractEntityManagerImpl - Mark transaction for rollback
[[ACTIVE] ExecuteThread: '5' for queue: 'weblogic.kernel.Default (self-tuning)'] INFO org.hibernate.engine.jdbc.internal.JdbcCoordinatorImpl - HHH000106: Forcing container resource cleanup on transaction completion
[[ACTIVE] ExecuteThread: '5' for queue: 'weblogic.kernel.Default (self-tuning)'] DEBUG org.hibernate.engine.jdbc.spi.SqlExceptionHelper - could not log warnings
java.sql.SQLException: Statement has already been closed为什么这回滚?
我正在尝试使用spring (1.9.2.RELEASE)、weblogic 12c、MySQL5.6.17。如果相关模拟,则在weblogic中启用两阶段提交。
你能告诉我如何正确地做这件事吗?
发布于 2015-12-24 23:52:03
用户id是自动生成的。保存方法无法在没有id的情况下在实体和dto之间建立连接。
https://stackoverflow.com/questions/34457644
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