考虑一下这个伪代码:
(defrc name
"string"
[a :A]
[:div a])其中,defrc将是一个宏,它将扩展到以下内容
(let [a (rum/react (atom :A))]
(rum/defc name < rum/reactive []
[:div a]))其中朗姆酒/defc本身就是一个宏。我想出了下面的代码:
(defmacro defrc
[name subj bindings & body]
(let [map-bindings# (apply array-map bindings)
keys# (keys map-bindings#)
vals# (vals map-bindings#)
atomised-vals# (atom-map vals#)]
`(let ~(vec (interleave keys# (map (fn [v] (list 'rum/react v)) (vals atomised-vals#))))
(rum/defc ~name < rum/reactive [] ~@body))))这几乎奏效了:
(macroexpand-all '(defrc aname
#_=> "string"
#_=> [a :A]
#_=> [:div a]))
(let* [a (rum/react #object[clojure.lang.Atom 0x727ed2e6 {:status :ready, :val nil}])] (rum/defc aname clojure.core/< rum/reactive [] [:div a]))然而,当使用时,它会导致语法错误:
ERROR: Syntax error at (clojure.core/< rum.core/reactive [] [:div a])这是因为内部宏没有被扩展吗?
发布于 2015-12-20 11:36:40
结果,宏工作正常,但出现了问题,因为<在语法引号中,它被扩展为clojure.core/<,而Rum只是从Rum的源代码中查找引用的<,相关片段:
...(cond
(and (empty? res) (symbol? x))
(recur {:name x} next nil)
(fn-body? xs) (assoc res :bodies (list xs))
(every? fn-body? xs) (assoc res :bodies xs)
(string? x) (recur (assoc res :doc x) next nil)
(= '< x) (recur res next :mixins)
(= mode :mixins)
(recur (update-in res [:mixins] (fnil conj []) x) next :mixins)
:else
(throw (IllegalArgumentException. (str "Syntax error at " xs))))...https://stackoverflow.com/questions/34372904
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