如何在不重置数组键的情况下移动第一个数组元素并生成新的数组

Question

下面是我的PHP代码，没有out：

<?php
$stack = array( 0 => array("orange", "banana", "apple", "raspberry"),1 => array("banana", "apple", "raspberry"),2 => array("apple", "raspberry"),'a' => array("raspberry"));

$temp = array_keys($stack);
array_shift($temp);

foreach($temp as $item){
    $dd[$item] = $stack[$item];
}
print_r($dd);
?>

产出如下：

Array
(
    [1] => Array
        (
            [0] => banana
            [1] => apple
            [2] => raspberry
        )

    [2] => Array
        (
            [0] => apple
            [1] => raspberry
        )

    [a] => Array
        (
            [0] => raspberry
        )

)

但是，当循环通过我打印数组时，第一个元素丢失了。它应该在数组列表中.

Answer 1

检查此代码，它将首先移位数组，最后添加数组，而不需要重置数组键：

我希望这对你有用..。

<?php

$stack = array( 0 => array("orange", "banana", "apple", "raspberry"),1 => array("banana", "apple", "raspberry"),2 => array("apple", "raspberry"),'a' => array("raspberry"));

$temp = array_keys($stack);
$tem = array_shift($temp);
$temp[] = $tem;
$dd = array();

foreach($temp as $item){
    $dd[$item] = $stack[$item];
}

echo"<pre>"; print_r($dd);
?>

产出：

阵列(1 =>阵列( =>香蕉1 =>苹果2 =>覆盆子) 2 =>阵列( =>苹果1 =>覆盆子) =>阵列( => raspberry ) =>阵列( =>橙1 =>香蕉2 => apple 3 => raspberry ) )

Answer 2

如果您只是想获取数组中第一个元素的值(而不删除它)，请使用reset($stack)。

array_shift()将从数组中移除元素并返回值。