带NSpredicate的IOS NSpredicate深子过滤

Question

matsDataObject *notebook1 = [matsDataObject dataObjectWithName:@"Notebook 1" children:nil];
matsDataObject *notebook2 = [matsDataObject dataObjectWithName:@"Notebook 2" children:nil];

matsDataObject *computer1 = [matsDataObject dataObjectWithName:@"Computer 1"
                                                      children:[NSArray arrayWithObjects:notebook1, notebook2, nil]];
matsDataObject *computer2 = [matsDataObject dataObjectWithName:@"Computer 2" children:nil];
matsDataObject *computer3 = [matsDataObject dataObjectWithName:@"Computer 3" children:nil];

matsDataObject *computer = [matsDataObject dataObjectWithName:@"Computers"
                                                     children:[NSArray arrayWithObjects:computer1, computer2, computer3, nil]];

这是我的NSobject：

计算机名为“计算机”，子计算机名为"NSarray，值为计算机1、计算机2和计算机3“。

计算机1名为"Computer 1“，子计算机名为"NSarray，其值为Notebook 1和Notebook 2”。

通过NSpredicate，我想在搜索“笔记本1”时获得父对象“计算机”

我试过的是：

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SUBQUERY(children, $child, $child.children.name CONTAINS[cd] %@).@count > 0",searchText];

和

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY children.children.name contains[cd] %@",searchText];

Answer 1

来结束这个问题。答案来自Willeke。

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"ANY children.@distinctUnionOfArrays.children.name contains[cd] %@",searchText];