使用xml-conduit解析XML时,我偶然发现了以下问题:当我有多个属性时,具有相同的基名,但前缀不同,只按(词法)顺序排列。
如果同时存在一个属性的前缀版本和非前缀版本,那么如何获得前缀值?
最小非工作示例:
Main.hs
{-# LANGUAGE OverloadedStrings #-}
module Main where
import Data.Text.Lazy (Text)
import qualified Data.Text.Lazy as T
import Text.XML (parseText, def, elementAttributes, documentRoot)
import Data.List (splitAt, drop)
main :: IO ()
main = do
putStrLn "Example1: only the first element is parsed"
putStrLn "========\n"
print $ elementAttributes . documentRoot <$> parseText def (T.unlines test)
putStrLn "Example2: this behaviour is independent of both having a prefix"
putStrLn "========\n"
print $ elementAttributes . documentRoot <$> parseText def (T.unlines $ dropAt 1 test)
putStrLn "Example3: also no difference if there is just one attribute with prefix"
putStrLn "========\n"
print $ elementAttributes . documentRoot <$> parseText def (T.unlines $ dropAt 2 test)
putStrLn "Example4: on its own the last element can be parsed"
putStrLn "========\n"
print $ elementAttributes . documentRoot <$> parseText def (T.unlines $ dropAt 1 $ dropAt 1 test)
putStrLn "==============="
putStrLn "Example1: it is always the first element parsed"
putStrLn "========\n"
print $ elementAttributes . documentRoot <$> parseText def (T.unlines test2)
putStrLn "Example2: really just the first"
putStrLn "========\n"
print $ elementAttributes . documentRoot <$> parseText def (T.unlines $ dropAt 1 test2)
test :: [Text]
test =["<Root"
, "here = \"ok\""
, "is:here = \"ok\""
, "not:here=\"nok\">"
,"</Root>"]
test2 :: [Text]
test2 =["<Root"
, "is:here = \"ok\""
, "here = \"ok\""
, "not:here=\"nok\">"
,"</Root>"]
dropAt :: Int -> [a] -> [a]
dropAt i xs = let (hd,tl) = splitAt i xs
in hd ++ drop 1 tlattr.cabal
build-depends: base >= 4.7 && < 5
, xml-conduit
, text
> stack exec attr
Example1: only the first element is parsed
========
Right (fromList [(Name {nameLocalName = "here", nameNamespace = Nothing, namePrefix = Nothing},"ok")])
Example2: this behaviour is independent of both having a prefix
========
Right (fromList [(Name {nameLocalName = "here", nameNamespace = Nothing, namePrefix = Just "is"},"ok")])
Example3: also no difference if there is just one attribute with prefix
========
Right (fromList [(Name {nameLocalName = "here", nameNamespace = Nothing, namePrefix = Nothing},"ok")])
Example4: on its own the last element can be parsed
========
Right (fromList [(Name {nameLocalName = "here", nameNamespace = Nothing, namePrefix = Just "not"},"nok")])
===============
Example1: only the first element is parsed
========
Right (fromList [(Name {nameLocalName = "here", nameNamespace = Nothing, namePrefix = Just "is"},"ok")])
Example2: this behaviour is independent of both having a prefix
========
Right (fromList [(Name {nameLocalName = "here", nameNamespace = Nothing, namePrefix = Nothing},"ok")])发布于 2015-12-15 01:01:30
引用Text.XML.Name
前缀在语义上并不重要;它们被包括进来只是为了简化传递解析。当将名称与Eq或Ord方法进行比较时,前缀将被忽略。
语义差异在于名称空间,因此以下内容解决了您的问题:
test :: [Text]
test =["<Root xmlns:is=\"http://example.com\" xmlns:not=\"http://example.com/2\""
, "here = \"ok\""
, "is:here = \"ok\""
, "not:here=\"nok\">"
,"</Root>"]这也是有意义的,因为我们可以在不同的地方不同地命名相同的名称空间,但应该是相同的。我认为,如果不将名称空间与前缀相关联,那么使用前缀也是无效的XML。
https://stackoverflow.com/questions/34266662
复制相似问题