当用户悬停在评等之上时,我希望能够将<div class="rate">Rate this product</div>替换为Bad, Better, Best的评等描述之一,并且在用户单击评等时使评等描述保持不变。我对Jquery相当陌生,所以我不知道从哪里开始。
HTML
<form action="" method="post">
<ul>
<li id="rate-1">
<label for="rating-1"><input type="radio" value="1" name="rating" id="rating-1" />1 star</label>
</li>
<li id="rate-2">
<label for="rating-2"><input type="radio" value="2" name="rating" id="rating-2" />2 stars</label>
</li>
<li id="rate-3">
<label for="rating-3"><input type="radio" value="3" name="rating" id="rating-3" />3 stars</label>
</li>
<li id="rate-4">
<label for="rating-4"><input type="radio" value="4" name="rating" id="rating-4" />4 stars</label>
</li>
<li id="rate-5">
<label for="rating-5"><input type="radio" value="5" name="rating" id="rating-5" />5 stars</label>
</li>
</ul>
<div class="rate">Rate this product</div>
</form>描述
<div>Bad</div>
<div>Better</div>
<div>Best</div>
<div>Great</div>
<div>Good</div>发布于 2015-12-07 06:03:15
对jQuery (使用https://jsfiddle.net/cwymmznw/小提琴)试试这个:
// HTML
<form action="" method="post">
<ul>
<li id="rate-1">
<label for="rating-1"><input type="radio" data-desc="Bad" value="1" name="rating" id="rating-1" />1 star</label>
</li>
<li id="rate-2">
<label for="rating-2"><input type="radio" data-desc="Good" value="2" name="rating" id="rating-2" />2 stars</label>
</li>
<li id="rate-3">
<label for="rating-3"><input type="radio" data-desc="Great" value="3" name="rating" id="rating-3" />3 stars</label>
</li>
<li id="rate-4">
<label for="rating-4"><input type="radio" data-desc="Better" value="4" name="rating" id="rating-4" />4 stars</label>
</li>
<li id="rate-5">
<label for="rating-5"><input type="radio" data-desc="Best" value="5" name="rating" id="rating-5" />5 stars</label>
</li>
</ul>
<div class="rate">Rate this product</div>
</form>
// JS
$('input').hover(function(e) {
$('.rate').text($(this).attr('data-desc'));
}, function(e) {
if ($('.selected')) {
$('.rate').text($('.selected').attr('data-desc'));
} else {
$('.rate').text('Rate this product');
}
});
$('input').click(function(e) {
$('.rate').text($(this).attr('data-desc'));
$('.selected').removeClass('selected');
$(this).addClass('selected');
});发布于 2015-12-07 05:53:32
试试这个代码:-
<form action="" method="post">
<ul>
<li id="rate-1">
<label for="rating-1"><input type="radio" value="1" class="rating" name="rating" id="rating-1" />1 star</label>
</li>
<li id="rate-2">
<label for="rating-2"><input type="radio" value="2" class="rating" name="rating" id="rating-2" />2 stars</label>
</li>
<li id="rate-3">
<label for="rating-3"><input type="radio" value="3" class="rating" name="rating" id="rating-3" />3 stars</label>
</li>
<li id="rate-4">
<label for="rating-4"><input type="radio" value="4" class="rating" name="rating" id="rating-4" />4 stars</label>
</li>
<li id="rate-5">
<label for="rating-5"><input type="radio" value="5" class="rating" name="rating" id="rating-5" />5 stars</label>
</li>
</ul>
<div class="rate">Rate this product</div>
</form>
<script src="http://code.jquery.com/jquery-1.11.3.min.js"></script>
<script>
$( "li" ).hover(
function() {
var rate = $( this ).find('.rating').val();
if(rate ==1){
$('.rate').html('bad');
}
if(rate == 2){
$('.rate').html('good');
}
if(rate == 3){
$('.rate').html('better');
}
if(rate == 4){
$('.rate').html('best');
}
if(rate == 5){
$('.rate').html('very best');
}
}, function() {
var str = "Rate this product";
$('.rate').html(str);
}
);
</script>js小提琴:- 链接
发布于 2015-12-07 05:53:40
你读过关于.hover()的文章吗?
$( "#yourSelector ).hover(
function() {
// show or hide here.
}
);https://stackoverflow.com/questions/34127180
复制相似问题