isspace和isalpha不算

Question

我的程序应该计算输入字符串中元音、辅音、数字和空格的数量。只是数数字而已。请帮帮忙。

#include<iostream>
using namespace std;

void counter(char string[], int count[]){
    int check_letter, check_digit, check_space;
    for(int i = 0; i < 99; i++){
        check_letter = isalpha(string[i]);
        if(check_letter == 1){
            string[i] = tolower(string[i]);
            if(string[i] == 'a' || string[i] == 'e' || string[i] == 'i' ||
                    string[i] == 'o' || string[i] == 'u'){
                count[0] = count[0] + 1;
            } else{
                count[1] = count[1] + 1;
            }
        }
        check_digit = isdigit(string[i]);
        if (check_digit == 1){
            count[2] = count[2] + 1;
        }
        check_space = isspace(string[i]);
        if(check_space == 1){
            count[3] = count[3] + 1;
        }
    }
}

main(){
    char string[100] = {};
    int count[4] = {};
    cout << "Please enter a string: ";
    cin.get(string, 100);
    cin.get();
    cout << string;
    counter(string, count);
    cout << "There are " << count[0] << " vowels.\nThere are " << count[1] <<
            " consonants.\nThere are " << count[2] << " digits.\nThere are " <<
            count[3] << " spaces.";
}

Answer 1

我修改了你的程序，它对我很好。您可以在if ()语句中直接检查isalpha() is位()的返回值，就像它们是bools一样。

#include<iostream>
using namespace std;

void counter(char string[], int count[]){
    for(int i = 0; i < 99; i++){
        if(isalpha(string[i])){
            string[i] = tolower(string[i]);
            if(string[i] == 'a' || string[i] == 'e' || string[i] == 'i' ||
                    string[i] == 'o' || string[i] == 'u'){
                count[0] = count[0] + 1;
            } else{
                count[1] = count[1] + 1;
            }
        }
        if (isdigit(string[i])){
            count[2] = count[2] + 1;
        }
        if(isspace(string[i])){
            count[3] = count[3] + 1;
        }
    }
}

main(){
    char string[100] = {};
    int count[4] = {};
    cout << "Please enter a string: ";
    cin.get(string, 100);
    cin.get();
    cout << string;
    counter(string, count);
    cout << "There are " << count[0] << " vowels.\nThere are " << count[1] <<
            " consonants.\nThere are " << count[2] << " digits.\nThere are " <<
            count[3] << " spaces.";
}

Answer 2

您的问题是假设isalpha、isdigit等在匹配时返回1：它们的文档表示返回"true“的非零值，"false”的返回值为零。

例如，来自std:isalpha文档在这里

返回值 如果字符是字母字符，则为非零值，否则为零。

如果将结果存储在bool中，或者直接在布尔上下文中测试结果(例如，if (...)条件)，那么转换将为您完成。

Answer 3

问题是check_letter、check_digit和check_space都应该是bool，而不是int。

因此，改变bool check_letter, check_digit, check_space;和if(check_letter)，而不是if(check_letter == 1)等等。

同时，请记住，"string“并不是一个非常聪明的命名变量的方法。