Android.mk、Android.mk和OCaml的通用链接

Question

我正在使用Android.mk工具包，并拥有这个Android.mk文件。

LOCAL_PATH := $(call my-dir)

include $(CLEAR_VARS)
LOCAL_MODULE := ocaml
LOCAL_SRC_FILES := ocaml/hello.so
include $(PREBUILT_SHARED_LIBRARY)

# ocamlfind -toolchain android ocamlopt \
# -output-complete-obj -cclib -shared hello.ml -o hello.so

include $(CLEAR_VARS)
LOCAL_MODULE := simple_test
LOCAL_SRC_FILES := main.c
# This name had to be that created shared library
LOCAL_STATIC_LIBRARIES := ocaml
LOCAL_C_INCLUDES += /home/gar/.opam/android_coding/lib/ocaml

include $(BUILD_EXECUTABLE)

这将成功编译并在/home/gar/ocaml_on_android/libs/armeabi、simple_test和hello.so中创建。

然而，当我在我的Nexus 7上运行代码时，我得到

CANNOT LINK EXECUTABLE: library "/home/gar/ocaml_on_android/obj/local/armeabi/hello.so" not found

这意味着它在编译时没有正确地链接。我如何编写这个Android.mk文件，以便在一个可执行文件中静态地编译所有内容？

编辑:注释之后，使用以下内容：

LOCAL_PATH := $(call my-dir)

include $(CLEAR_VARS)
LOCAL_MODULE := ocaml
LOCAL_SRC_FILES := ocaml/hello.so
include $(PREBUILT_SHARED_LIBRARY)

# ocamlfind -toolchain android ocamlopt \
# -output-complete-obj -cclib -shared hello.ml -o hello.so

include $(CLEAR_VARS)
LOCAL_MODULE := simple_test
LOCAL_SRC_FILES := wrapper.c
# This name had to be that created shared library
LOCAL_SHARED_LIBRARIES := hello.so
LOCAL_C_INCLUDES += /home/gar/.opam/android_coding/lib/ocaml

include $(BUILD_EXECUTABLE)

在项目的libs文件夹中，我仍然有两个对象，hello.so和simple_test exectuable，我希望只看到一个对象。对于LOCAL_SHARED_LIBRARIES，不确定是否需要将模块名、ocaml或实际的共享对象hello.so。无论是哪种情况，仍然会在libs目录中生成两个对象。

EDIT2:我现在为我的Android.mk准备了这个

LOCAL_PATH := $(call my-dir)

include $(CLEAR_VARS)
LOCAL_MODULE := ocaml
LOCAL_SRC_FILES := ocaml/hello.so
include $(PREBUILT_SHARED_LIBRARY)

# ocamlfind -toolchain android ocamlopt \
# -output-complete-obj -cclib -shared hello.ml -o hello.so

include $(CLEAR_VARS)
LOCAL_MODULE := simple_test
LOCAL_SRC_FILES := wrapper.c
# This name had to be that created shared library
LOCAL_CFLAGS := -Wl,-Bstatic -static
LOCAL_SHARED_LIBRARIES := hello ocaml
LOCAL_C_INCLUDES += /home/gar/.opam/android_coding/lib/ocaml

include $(BUILD_EXECUTABLE)

当我检查创建的可执行文件时，我仍然看到它取决于共享库。

arm-linux-androideabi-readelf -d simple_test | grep NEEDED
 0x00000001 (NEEDED)                     Shared library: [/home/gar/asm_on_android/obj/local/armeabi/hello.so]
 0x00000001 (NEEDED)                     Shared library: [libstdc++.so]
 0x00000001 (NEEDED)                     Shared library: [libm.so]
 0x00000001 (NEEDED)                     Shared library: [libc.so]
 0x00000001 (NEEDED)                     Shared library: [libdl.so]

我还在设备上的shell上尝试了LD_LIBRARY_PATH=. ./simple_test命令，但得到了以下错误：

 LD_LIBRARY_PATH= . ./simple_test                                                                 
sh: ./simple_test[1]: syntax error: '\
                                       4' unexpected

Answer 1

感谢亚历克斯的帮助。

我决定暂时跳过Android，而只是选择了一个直接的Makefile解决方案，这是可行的。

这是Makefile

cc := arm-linux-androideabi-gcc

sys_root := /Users/Edgar/.opam/4.02.3+32bit/lib/android-ndk/platforms/android-21/arch-arm

includes := /Users/Edgar/.opam/4.02.3+32bit/arm-linux-androideabi/include

ml_includes := /Users/Edgar/.opam/4.02.3+32bit/arm-linux-androideabi/lib/ocaml/

libs := /Users/Edgar/.opam/4.02.3+32bit/arm-linux-androideabi/lib

# Be sure to do export LD_LIBRARY_PATH=. and then run the program.
# Not sure how to do static linking yet, this will only dynamically
# link the program
complete: lib
    $(cc) --sysroot $(sys_root) -I$(includes) -L$(libs) \
    -pie -I$(ml_includes) hello.so main.c -o Finished

lib:
    ocamlfind -toolchain android ocamlopt -output-complete-obj \
    -cclib '-lm -shared' hello.ml -o hello.so

# This is a pure OCaml exectuable
exec:
    ocamlfind -toolchain android ocamlopt \
    -verbose -ccopt '-fPIE' -cclib '-pie' hello.ml -o hello

.PHONY: clean
clean:
    @rm -rf *.{cmi,cmt,o,cmx,so} Finished

...Substitute您的名字和路径，酌情。还把回购放在这里，android

Answer 2

共享库就是这样使用的。您可以在hello.so可执行文件附近将simple_test推送到设备上。

Android.mk的语法应该是

LOCAL_SHARED_LIBRARIES := ocaml

在shell命令行上，使用

LD_LIBRARY_PATH=. ./simple_test