android Simperium简单待办演示代码中的错误

Question

我下载了演示代码。

运行代码后：

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我要拿到这个屏幕。我在其他设备上用相同的用户名和id登录，但没有发生任何事情。

在输入文本时，我将得到以下错误：

11-30 18:29:58.731  14566-16417/com.simperium.simpletodo E/SQLiteDatabase﹕ Error inserting bucketName=todo changeVersion=
    android.database.sqlite.SQLiteConstraintException: UNIQUE constraint failed: changeVersions.bucketName (code 2067)
            at android.database.sqlite.SQLiteConnection.nativeExecuteForLastInsertedRowId(Native Method)
            at android.database.sqlite.SQLiteConnection.executeForLastInsertedRowId(SQLiteConnection.java:780)
            at android.database.sqlite.SQLiteSession.executeForLastInsertedRowId(SQLiteSession.java:788)
            at android.database.sqlite.SQLiteStatement.executeInsert(SQLiteStatement.java:86)
            at android.database.sqlite.SQLiteDatabase.insertWithOnConflict(SQLiteDatabase.java:1471)
            at android.database.sqlite.SQLiteDatabase.insert(SQLiteDatabase.java:1341)
            at com.simperium.android.GhostStore.setChangeVersion(GhostStore.java:98)
            at com.simperium.client.Bucket.setChangeVersion(Bucket.java:416)
            at com.simperium.client.Bucket.indexComplete(Bucket.java:411)
            at com.simperium.client.Channel$IndexProcessor.notifyDone(Channel.java:1126)
            at com.simperium.client.Channel$IndexProcessor.next(Channel.java:1039)
            at com.simperium.client.Channel$IndexProcessor.addIndexPage(Channel.java:1107)
            at com.simperium.client.Channel$IndexProcessor.start(Channel.java:994)
            at com.simperium.client.Channel.updateIndex(Channel.java:397)
            at com.simperium.client.Channel.access$100(Channel.java:38)
            at com.simperium.client.Channel$2.execute(Channel.java:187)
            at com.simperium.client.Channel$CommandInvoker.executeCommand(Channel.java:743)
            at com.simperium.client.Channel.executeCommand(Channel.java:713)
            at com.simperium.client.Channel.receiveMessage(Channel.java:667)
            at com.simperium.android.WebSocketManager.onMessage(WebSocketManager.java:420)
            at com.simperium.android.WebSocketManager$2.onMessage(WebSocketManager.java:211)
            at com.simperium.android.AsyncWebSocketProvider$1$2.onStringAvailable(AsyncWebSocketProvider.java:85)
            at com.koushikdutta.async.http.WebSocketImpl$1.onMessage(WebSocketImpl.java:88)
            at com.koushikdutta.async.http.HybiParser.emitFrame(HybiParser.java:420)
            at com.koushikdutta.async.http.HybiParser.access$800(HybiParser.java:46)
            at com.koushikdutta.async.http.HybiParser$5.onDataAvailable(HybiParser.java:197)
            at com.koushikdutta.async.DataEmitterReader.handlePendingData(DataEmitterReader.java:24)
            at com.koushikdutta.async.DataEmitterReader.onDataAvailable(DataEmitterReader.java:41)
            at com.koushikdutta.async.Util.emitAllData(Util.java:22)
            at com.koushikdutta.async.AsyncSSLSocketWrapper.onDataAvailable(AsyncSSLSocketWrapper.java:230)
            at com.koushikdutta.async.AsyncSSLSocketWrapper$5.onDataAvailable(AsyncSSLSocketWrapper.java:217)
            at com.koushikdutta.async.Util.emitAllData(Util.java:22)
            at com.koushikdutta.async.AsyncNetworkSocket.onReadable(AsyncNetworkSocket.java:146)
            at com.koushikdutta.async.AsyncServer.runLoop(AsyncServer.java:788)
            at com.koushikdutta.async.AsyncServer.run(AsyncServer.java:626)
            at com.koushikdutta.async.AsyncServer.access$700(AsyncServer.java:41)
            at com.koushikdutta.async.AsyncServer$13.run(AsyncServer.java:568)

如果有人知道，请帮忙！

Answer 1

演示应用程序依赖于软键盘来添加新的项目，所以请确保在您的模拟器或设备中启用它。

我将研究sql错误，但它似乎只显示在模拟器日志中，而不显示在实际设备上。

Answer 2

错误声明：

UNIQUE constraint failed: changeVersions.bucketName

bucketName有一个唯一的约束，这意味着每个新插入的值都必须是唯一的。

因此，您尝试使用数据库中已经存在的bucketName插入一个对象。

如果您认为可以使用相同的bucketName拥有多个对象，请删除该约束。

如果不应该，在插入之前检查一下是否已经有了，并优雅地处理它。