我使用的是野蝇8.2.0。我想从一开始就加载Springconfig.xml,但是它没有成功。我做错什么了?
这是我的web.xml。
<?xml version="1.0" encoding="UTF-8"?>1.xsd“version="3.1">
<display-name>BQP</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>src/main/resources/spring-config*.xml</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<servlet>
<servlet-name>Resteasy</servlet-name>
<servlet-class>org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Resteasy</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
<context-param>
<param-name>javax.ws.rs.Application</param-name>
<param-value>com.bionic.rest.ApplicationConfiguration</param-value>
</context-param>
<context-param>
<param-name>resteasy.servlet.mapping.prefix</param-name>
<param-value>/rest</param-value>
</context-param>
<listener>
<listener-class>org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap</listener-class>
</listener>
发布于 2015-11-18 11:10:53
对于spring,您可以在应用程序启动时加载配置xml表单web.xml,如下所示:
<!-- Spring MVC -->
<servlet>
<servlet-name>Spring MVC Dispatcher Servlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/app-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>https://stackoverflow.com/questions/33778368
复制相似问题