首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >antlr4:语法模糊,左递归,两者兼而有之?

antlr4:语法模糊,左递归,两者兼而有之?
EN

Stack Overflow用户
提问于 2015-11-17 07:33:43
回答 1查看 131关注 0票数 0

如下所示,我的语法没有编译。返回的错误(来自antlr4 maven插件)是:

代码语言:javascript
复制
[INFO] --- antlr4-maven-plugin:4.3:antlr4 (default-cli) @ beebell ---
[INFO] ANTLR 4: Processing source directory /Users/kodecharlie/workspace/beebell/src/main/antlr4
[INFO] Processing grammar: DateRange.g4
org\antlr\v4\parse\GrammarTreeVisitor.g: node from line 13:87 mismatched tree node: startTime expecting <UP>
org\antlr\v4\parse\GrammarTreeVisitor.g: node from after line 13:87 mismatched tree node: RULE expecting <UP>
org\antlr\v4\parse\GrammarTreeVisitor.g: node from line 13:87 mismatched tree node: startTime expecting <UP>
org\antlr\v4\parse\GrammarTreeVisitor.g: node from after line 13:87 mismatched tree node: RULE expecting <UP>
org\antlr\v4\parse\GrammarTreeVisitor.g: node from line 13:87 mismatched tree node: startTime expecting <UP>
org\antlr\v4\parse\GrammarTreeVisitor.g: node from after line 13:87 mismatched tree node: RULE expecting <UP>
org\antlr\v4\parse\GrammarTreeVisitor.g: node from line 13:87 mismatched tree node: startTime expecting <UP>
org\antlr\v4\parse\GrammarTreeVisitor.g: node from after line 13:87 mismatched tree node: RULE expecting <UP>
[ERROR] error(20):  internal error: Rule HOUR undefined 
[ERROR] error(20):  internal error: Rule MINUTE undefined 
[ERROR] error(20):  internal error: Rule SECOND undefined 
[ERROR] error(20):  internal error: Rule HOUR undefined 
[ERROR] error(20):  internal error: Rule MINUTE undefined 

我可以看出语法是如何被混淆的--例如,两个数字是一分钟、秒还是小时(或者可能是一年的开始)。但有几篇文章指出,这个错误是由左递归造成的。

你能说出发生了什么事吗?

谢谢。下面是语法:

代码语言:javascript
复制
grammar DateRange;

range     : startDate (THRU endDate)? | 'Every' LONG_DAY 'from' startDate THRU endDate ;

startDate : dateTime ;
endDate   : dateTime ;
dateTime  : GMTOFF | SHRT_MDY | YYYYMMDD | (WEEK_DAY)? LONG_MDY ;

// Dates.
GMTOFF    : YYYYMMDD 'T' HOUR ':' MINUTE ':' SECOND ('-'|'+') HOUR ':' MINUTE ;
YYYYMMDD  : YEAR '-' MOY '-' DOM ;
SHRT_MDY  : MOY ('/' | '-') DOM ('/' | '-') YEAR ;
LONG_MDY  : (SHRT_MNTH '.'? | LONG_MNTH) WS DOM ','? (WS YEAR (','? WS TIMESPAN)? | WS startTime)? ;

YEAR      : DIGIT DIGIT DIGIT DIGIT ;   // year
MOY       : (DIGIT | DIGIT DIGIT) ;     // month of year.
DOM       : (DIGIT | DIGIT DIGIT) ;     // day of month.
TIMESPAN  : startTime (WS THRU WS endTime)? ;

// Time-of-day.
startTime : TOD ;
endTime   : TOD ;
TOD       : NOON | HOUR2 (':' MINUTE)? WS? MERIDIAN ;
NOON      : 'noon' ;
HOUR2     : (DIGIT | DIGIT DIGIT) ;
MERIDIAN  : 'AM' | 'am' | 'PM' | 'pm' ;

// 24-hour clock.  Sanity-check range in listener.
HOUR      : DIGIT DIGIT ;
MINUTE    : DIGIT DIGIT ;
SECOND    : DIGIT DIGIT ;

// Range verb.
THRU      : WS ('-'|'to') WS -> skip ;

// Weekdays.
WEEK_DAY  : (SHRT_DAY | LONG_DAY) ','? WS ;
SHRT_DAY  : 'Sun' | 'Mon' | 'Tue' | 'Wed' | 'Thu' | 'Fri' | 'Sat' -> skip ;
LONG_DAY  : 'Sunday' | 'Monday' | 'Tuesday' | 'Wednesday' | 'Thursday' | 'Friday' | 'Saturday' -> skip ;

// Months.
SHRT_MNTH : 'Jan' | 'Feb' | 'Mar' | 'Apr' | 'May' | 'Jun' | 'Jul' | 'Aug' | 'Sep' | 'Oct' | 'Nov' | 'Dec' ;
LONG_MNTH : 'January' | 'February' | 'March' | 'April' | 'May' | 'June' | 'July' | 'August' | 'September' | 'October' | 'November' | 'December' ;

DIGIT     : [0-9] ;
WS        : [ \t\r\n]+ -> skip ;
EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2016-03-03 01:25:14

我通过为每个数字序列(长度为1、2、3或4)设置唯一的产生规则来解决这个问题。同时,我简化了几个规则--实际上,试图使生产规则的替代方案更加简单。总之,这是最后的结果,它确实编译了:

代码语言:javascript
复制
grammar DateRange;

range     : 'Every' WS longDay WS 'from' WS startDate THRU endDate
          | startDate THRU endDate
          | startDate
          ;

startDate : dateTime ; endDate   : dateTime ; dateTime  : utc
          | shrtMdy
          | yyyymmdd
          | longMdy
          | weekDay ','? WS longMdy
          ;

// Dates.
utc       : yyyymmdd 'T' hour ':' minute ':' second ('-'|'+') hour ':' minute ;
yyyymmdd  : year '-' moy '-' dom ;
shrtMdy : moy ('/' | '-') dom ('/' | '-') year ;
longMdy   : longMonth WS dom ','? optYearAndOrTime?
          | shrtMonth '.'? WS dom ','? optYearAndOrTime?
          ;

optYearAndOrTime : WS year ','? WS timespan
                 | WS year
                 | WS timespan
                 ;

fragment DIGIT : [0-9] ;
ONE_DIGIT    : DIGIT ;
TWO_DIGITS   : DIGIT ONE_DIGIT ;
THREE_DIGITS : DIGIT TWO_DIGITS ;
FOUR_DIGITS  : DIGIT THREE_DIGITS ;

year      : FOUR_DIGITS ;                   // year
moy       : ONE_DIGIT | TWO_DIGITS ;        // month of year.
dom       : ONE_DIGIT | TWO_DIGITS ;        // day of month.
timespan  : (tod THRU tod) | tod ;

// Time-of-day.
tod       : noon | (hour2 (':' minute)? WS? meridian?) ;
noon      : 'noon' ; hour2     : ONE_DIGIT | TWO_DIGITS ;
meridian  : ('AM' | 'am' | 'PM' | 'pm' | 'a.m.' | 'p.m.') ;

// 24-hour clock.  Sanity-check range in listener.
hour      : TWO_DIGITS ;
minute    : TWO_DIGITS ;
second    : TWO_DIGITS ;   // we do not use seconds.

// Range verb.
THRU      : WS? ('-'|'–'|'to') WS? ;

// Weekdays.
weekDay   : shrtDay | longDay ; shrtDay   : 'Sun' | 'Mon' | 'Tue' | 'Wed' | 'Thu' | 'Fri' | 'Sat' ; longDay   : 'Sunday' | 'Monday' | 'Tuesday' | 'Wednesday' | 'Thursday' | 'Friday' | 'Saturday' ;

// Months.
shrtMonth : 'Jan' | 'Feb' | 'Mar' | 'Apr' | 'May' | 'Jun' | 'Jul' | 'Aug' | 'Sep' | 'Oct' | 'Nov' | 'Dec' ;
longMonth : 'January' | 'February' | 'March' | 'April' | 'May' | 'June' | 'July' | 'August' | 'September' | 'October' | 'November' | 'December' ;

WS        : ~[a-zA-Z0-9,.:]+ ;
票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/33751423

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档