我发现了通过谷歌生成质数的多种方法,比如wiki:miscellaneous#One-liners中的质数,它通常以如下形式出现:
sieve (p:px) = p : sieve [n | n <- px, mod n p /= 0]不使用集合表示法,生成质数的简单方法是什么?
发布于 2015-11-04 03:59:09
是的,只要把列表理解符号翻译成它的基本含义就可以了
sieve (p:px) = p : sieve (filter (\n -> mod n p /= 0) px)发布于 2015-11-04 04:06:42
另一个低效但简单的状态表达式是
nubBy (((==0).).rem) [2..]或带点
nubBy (\x y -> x `rem` y == 0) [2..]ps。nubBy在Data.List
> take 100 $ nubBy (\x y -> x `rem` y == 0) [2..]
[2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97,
101,103,107,109,113,127,131,137,139,149,151,157,163,167,173,179,181,191,
193,197,199,211,223,227,229,233,239,241,251,257,263,269,271,277,281,283,
293,307,311,313,317,331,337,347,349,353,359,367,373,379,383,389,397,401,
409,419,421,431,433,439,443,449,457,461,463,467,479,487,491,499,503,509,
521,523,541]https://stackoverflow.com/questions/33513338
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